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Ann [662]
3 years ago
9

Triangle DEF is shown below.

Mathematics
1 answer:
Svetach [21]3 years ago
6 0

Answer:

Step-by-step explanation:

13

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tyler says that an equivalent expression for 2 exponent of 3 times 5 exponent is 10 exponent of 9 is he correct?
irakobra [83]

Answer:

pls reword then i can help

Step-by-step explanation:

6 0
4 years ago
Determine whether each of the following products is rational or irrational.
ankoles [38]

Answer:

-irrational

-rational

-rational

-irrational

__________________________________________________________quick and easy way is to see if the squares are perfect squares, like square root seven is irrational, so the answer is irrational. square root 9 is 3, which is rational, so its rational.

brainliest is appreciated :)

6 0
3 years ago
What is 2/3 in percent form
dexar [7]
2/3 is just .6666666666 and the 6 goes on forever
6 0
3 years ago
Read 2 more answers
Scientists predict that there is a 0.8 chance that there will be an earthquake in San Francisco this year. How likely is that th
Firlakuza [10]

Answer:

80%

Step-by-step explanation:

8 0
3 years ago
businessText message users receive or send an average of 62.7 text messages per day. How many text messages does a text message
KiRa [710]

Answer:

(a) The probability that a text message user receives or sends three messages per hour is 0.2180.

(b) The probability that a text message user receives or sends more than three messages per hour is 0.2667.

Step-by-step explanation:

Let <em>X</em> = number of text messages receive or send in an hour.

The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em>.

It is provided that users receive or send 62.7 text messages in 24 hours.

Then the average number of text messages received or sent in an hour is: \lambda=\frac{62.7}{24}= 2.6125.

The probability of a random variable can be computed using the formula:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!} ;\ x=0, 1, 2, 3, ...

(a)

Compute the probability that a text message user receives or sends three messages per hour as follows:

P(X=3)=\frac{e^{-2.6125}(2.6125)^{3}}{3!} =0.21798\approx0.2180

Thus, the probability that a text message user receives or sends three messages per hour is 0.2180.

(b)

Compute the probability that a text message user receives or sends more than three messages per hour as follows:

P (X > 3) = 1 - P (X ≤ 3)

              = 1 - P (X = 0) - P (X = 1) - P (X = 2) - P (X = 3)

             =1-\frac{e^{-2.6125}(2.6125)^{0}}{0!}-\frac{e^{-2.6125}(2.6125)^{1}}{1!}-\frac{e^{-2.6125}(2.6125)^{2}}{2!}-\frac{e^{-2.6125}(2.6125)^{3}}{3!}\\=1-0.0734-0.1916-0.2503-0.2180\\=0.2667

Thus, the probability that a text message user receives or sends more than three messages per hour is 0.2667.

6 0
3 years ago
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