The product to your question is 2a+b
For this case we have the following polynomials:
3x2
x2y + 3xy2 + 1
We have then:
For 3x2:
Classification: polynomial of one variable:
Degree: 2
For x2y + 3xy2 + 1:
Classification: polynomial of two variables
Degree: 2 + 1 = 3
Answer:
The polynomial 3x2 is of one variable with a degree of 2.
The polynomial x2y + 3xy2 + 1 is of two variables a with a degree of 3.
Answer:
The answer can be calculated by doing the following steps;
Step-by-step explanation:
Answer:
2/10 + 7/10
9/10
Step-by-step explanation:
I did the test.
15
5x-2y=9......(1)
6x+ky=4......(2)
slope of eqn i= -5/-2
=5/2
slope of eqn ii = -6/k
since the line are perpendicular
5/2 * -6/k = -1
-30= -2k
k=15
