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nlexa [21]
3 years ago
7

One flickeronie and 2 flickeronies

Mathematics
1 answer:
Natali [406]3 years ago
3 0

Answer: 7 hours left!

Step-by-step explanation:

She had used up 12 hours and 45 minutes. 7 hours and 15 minutes left, but if you're including the minutes, then it's 7 hours and 15 minutes. Good luck! :D

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Which expressions are equivalent to 2(4f+2g)?
zzz [600]
Answers are C) 8f+4g D) 4(2f+g) & E) 4f+4f+4g
4 0
3 years ago
The coordinate grid shows points a through k. Which points are solutions to the system of inequalities 2x+y 8 please help this i
andre [41]

Answer:

The points that verify the system of inequalities are:

point E, pointF, and point G.

Step-by-step explanation:

Please see the attached image that illustrates the boundary lines in your system of inequalities.

The boundary line for the inequality 2x+y is depicted in green, while the boundary line for the inequality 2x-4y>8 is depicted in red.

By solving for y in each inequality, we understand which half-plane should be considered for the inequality:

First inequality (green boundary line) :

2x+y

This means that we are to consider the points below the green boundary line.

Second inequality (red boundary line) :

2x-4y >8\\2x-8>4y\\y

This means we have to consider the points below the red boundary line.

Recall as well that both conditions we arrived at have to be satisfied by the points that are solutions of both inequalities.

From the image, we can see that there are only three points that reside at the same time below the green and the red boundary lines. These points are: point E, pointF, and point G.

On the other hand, we have two points that lie on a boundary line (point J and H), but they should be ignored, since the system of inequalities contain just inequality symbols < or >, and not the "equal" sign.

5 0
3 years ago
(2^8 x 3^−5 x 6^0)−2 x 3 to the power of negative 2 over 2 to the power of 3, whole to the power of 4 x 2^28
Veronika [31]

(2^8\cdot3^{-5}\cdot6^0)^{-2}\cdot\left(\dfrac{3^{-2}}{2^3}\right)^4\cdot2^{28}\\\\=(2^8)^{-2}\cdot(3^{-5})^{-2}\cdot1^{-2}\cdot\dfrac{(3^{-2})^4}{(2^3)^4}\cdot2^{28}\\\\=2^{-16}\cdot3^{10}\cdot\dfrac{3^{-8}}{2^{12}}\cdot2^{28}\\\\=2^{-16}\cdot2^{28}\cdot2^{-12}\cdot3^{10}\cdot3^{-8}\\\\=2^{-16+28+(-12)}\cdot3^{10+(-8)}\\\\=2^0\cdot3^2=1\cdot9=\boxed{9}\\\\Used:\\\\(a\cdot b)^n=a^n\cdot b^n\\\\(a^n)^m=a^{n\cdot m}\\\\a^n\cdot a^m=a^{n+m}\\\\a^{-n}=\dfrac{1}{a^n}

4 0
3 years ago
Read 2 more answers
What vaulue of K anwsers the qestion.....K -4 = 1/256 please hurry its the last one i cant fail :(
iogann1982 [59]

K=4+1/256

If this is a multiple choice question, please provide the choices ;)

4 0
3 years ago
I need help pls pls pls
serg [7]

Answer:

e. 55 miles hope that helped

6 0
3 years ago
Read 2 more answers
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