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dem82 [27]
2 years ago
9

HELP

Mathematics
1 answer:
Harrizon [31]2 years ago
5 0

Answer:

Step-by-step explanation:

y - 2 = 2/3(x - 6)

y - 2 = 2/3x - 4

y = 2/3x - 2

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− <br> 1<br> ​ <br> + <br> −81<br> ​ <br> − <br> 16<br> ​ <br> − <br> −1<br> ​
Nataliya [291]

Answer: it is -97

Step-by-step explanation:

because you break it down

-1-81-16+1 ( and the -- turns into a + )

( get rid of the + )

3 0
3 years ago
Solve::::::::::::::::<br><img src="https://tex.z-dn.net/?f=%20%5Csf%20%5C%3A%203%28y%20%2B%203%29%20-%2010%20%3D%202y%20%2B%201"
Nataly_w [17]

\sf{\pmb{ANSWER : }}

let the equation be

\sf \: 3(y + 3) - 10 = 2y + 1

\sf \: 3y + 9 - 10 = 2y + 1

\sf \:  3y - 1 = 2y + 1

\sf \:  3y -2y = 1 + 1

\purple {{{\sf y = 2 }}}

https://brainly.in/app/profile/18799022

6 0
2 years ago
Read 2 more answers
A sandwich shop has 18 tables. Each table seats up to 4 people. To find the greatest number of people that can be seated, you ca
dedylja [7]

c.multiply each side by 4

7 0
3 years ago
Mrs. johnson's and mr. wei's classes are participating in the Meridian School arts and crafts exhibit. Their spaces will be next
Nat2105 [25]

Answer:

See explanation

Step-by-step explanation:

Ms. Johnson space has 48 carpet squares.

Mr. Wei space has 36 carpet squares.

Factorize these two numbers:

48=2\cdot 2\cdot 2\cdot 2\cdot 3\\ \\36=2\cdot 2\cdot 3\cdot 3

All common factors are 1, 2, 3, 4, 6, 12

<u>All possibilities:</u>

1. If Ms. Johnson space width and Mr. Wei space width is 1 carpet, then Ms. Johnson space length is 48 carpets and Mr. Wei space length is 36 carpets.

2. If Ms. Johnson space width and Mr. Wei space width is 2 carpets, then Ms. Johnson space length is 24 carpets and Mr. Wei space length is 18 carpets.

3. If Ms. Johnson space width and Mr. Wei space width is 3 carpets, then Ms. Johnson space length is 16 carpets and Mr. Wei space length is 12 carpets.

4. If Ms. Johnson space width and Mr. Wei space width is 4 carpets, then Ms. Johnson space length is 12 carpets and Mr. Wei space length is 9 carpets.

5. If Ms. Johnson space width and Mr. Wei space width is 6 carpets, then Ms. Johnson space length is 8 carpets and Mr. Wei space length is 6 carpets.

6. If Ms. Johnson space width and Mr. Wei space width is 12 carpets, then Ms. Johnson space length is 4 carpets and Mr. Wei space length is 3 carpets.

4 0
3 years ago
Read 2 more answers
I need help please help my test is timed..
kipiarov [429]

Answer:

I think it would be -1  its hard to explain but I am very positive

Step-by-step explanation:

7 0
2 years ago
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