Answer:
Recursive
a(1) = 9 ; a(n+1) = 3 * a(n)
Explicit
a(n) = 9 * 3^(n-1)
Well 57+59+61= 177 so the answer is 57
Answer:
C
Step-by-step explanation:
In general for arithmetic sequences, recursive formulas are of the form
aₙ = aₙ₋₁ + d,
and the explicit formula (like tₙ in your problem), are of the form
aₙ = a₁ + (n - 1)d,
where d is the common difference. So converting between the two of these isn't so bad. In this case, your problem wants you to have an idea of what t₁ is (well, every answer says it's -5, so there you are) and what tₙ₊₁ is. Using the formulas above and your given tₙ = -5 + (n - 1)78, we can see that the common difference is 78, so no matter what we get ourselves into, the constant being added on at the end should be 78. That automatically throws out answer choice D.
But to narrow it down between the rest of them, you want to use the general form for the recursive formula and substitute (n + 1) for every instance of n. This will let you find tₙ₊₁ to match the requirements of your answer choices. So
tₙ₊₁ = t₍ₙ₊₁₎₋₁ + d ... Simplify the subscript
tₙ₊₁ = tₙ + d
Therefore, your formula for tₙ₊₁ = tₙ + 78, which is answer choice C.
Step-by-step explanation:
1. (2+4+1)/9 = 7/9
2. 2 1/3 + 2/3 = 2 + (1+2)/3 = 2 + 3/3 = 2+1 = 3
3. 1 1/5 + 2 3/5 = 1+2 + 1/5 + 3/5 = 3 + (1+3)/5 =
3 4/5
4. 5/6 + 2/10 + 1/5 = 5/6 + 1/5 + 1/5 = 5/6 + 2/5
= (5×5)/(6×5) + (2×6)/(5×6)
= 25/30 + 12/30
= (25+12)/30
= 37/30 = 1 7/30
5. 3 1/2 + 4 2/3
= 3+4 + 1/2 + 2/3
= 7 + (1×3)/(2×3) + (2×2)/(3×2)
= 7 + 3/6 + 4/6
= 7 + (3+4)/6 = 7 7/6 = 8 1/6
6. 9/13 - 5/13 = (9-5)/13 = 4/13
7. 7 6/8 - 5 2/8
= (7-5) + (6/8 - 2/8)
= 2 + 4/8
= 2 1/2
8. 2/3 - 3/7
= (2×7)/(3×7) - (3×3)/(7×3)
= 14/21 - 9/21 = (14-9)/21 = 5/21
9. 11 1/5 - 5 4/5
= 10 6/5 - 5 4/5
= (10-5) + (6/5 - 4/5)
= 5 + 2/5 = 5 2/5
10. 15 4/5 - 7 7/10
= (15-7) + (4/5 - 7/10)
= 8 + (4×2)/(5×2) - 7/10
= 8 + 8/10 - 7/10
= 8 + 1/10
= 8 1/10
I would start off by taking away 1a. That would make the problem be 56ab3-35b.I only took away 1 because each have at least 1a and is okay to do.
Next I would deal with the variable b. I would cross of 1 b. That's because both sides have at least 1b. Now, it's shortened to be 56ab2-35.
Since you cannot take away anymore variables, you have to deal with 56 and 35. I start small with dividing each by 2. I am trying to see what the greatest number could be while making the numbers still be whole. That turns 56 into 28 when it's cut in half. The 35 now turns into 17.5.
I would assume your teacher would want the numbers to be whole. seeing as though when 35 is cut in half and makes a decimal number, I would leave them. What I mean by that is to leave the numbers as 56 and 35.
So, that means the answer is 56ab2-35.
I hope this helps!! (And makes sense)
