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sineoko [7]
3 years ago
15

What is the length of the longest side of a triangle that has vertices at (-2,6) (-4,6) and (-4,4)?

Mathematics
1 answer:
zalisa [80]3 years ago
6 0

Length (2, 6) to (-4, 6) is sqrt((x2 - x1))^2 + (y2 - y1)^2) = sqrt((-4 -2)^2 + (6 - 6)^2) = sqrt((-6)^2 + 0) = 6

Length (2, 6) to (-4, 4) is sqrt((-4 - 2)^2 + (4 - 6)^2) = sqrt((-6)^2 + (-2)^2) = sqrt(36 + 4) = sqrt(40)  = 2sqrt(10) units

Length (-4, 6) to (-4, 4) is sqrt((-4 - (-4))^2 + (4 - 6)^2) = sqrt(0^2 + (-2)^2) = 2

So the length of the longest side is 2sqrt(10) units
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3 years ago
I rent a gym for $150 for 30 students another time I rent the gym for $270 for 70 students I need to find a fixed rate
kirza4 [7]

Answer:

Fixed rate is $60.

Step-by-step explanation:

Let us consider per student charge be 'x'.

Let us consider fixed rate be 'b'

Given:

I rent a gym for $150 for 30 students.

So we can say that;

Total amount is equal to sum of number of students multiplied by per student charge and fixed rate.

framing in equation form we get;

30x+b=150 \ \ \ \ equation \ 1

Also Given:

another time I rent the gym for $270 for 70 students.

So we can say that;

Total amount is equal to sum of number of students multiplied by per student charge and fixed rate.

framing in equation form we get;

70x+b=270 \ \ \ \ equation \ 2

Now we will subtract equation 1 from equation 2 we get;

70x+b-(30x+b)=270-150\\\\70x+b-30x-b=120\\\\40x=120

Dividing both side by 40 we get;

\frac{40x}{40}=\frac{120}{40}\\\\x=\$3

Now we will substitute the value of x in equation 1 we get;

30x+b=150\\\\30\times3+b=150\\\\90+b=150\\\\b=150-90 =\$60

So we can say that the equation can be written as;

y =3x+60

Hence we can say that fixed rate is $60 and per student charge is $3.

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3 years ago
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