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sineoko [7]
2 years ago
15

What is the length of the longest side of a triangle that has vertices at (-2,6) (-4,6) and (-4,4)?

Mathematics
1 answer:
zalisa [80]2 years ago
6 0

Length (2, 6) to (-4, 6) is sqrt((x2 - x1))^2 + (y2 - y1)^2) = sqrt((-4 -2)^2 + (6 - 6)^2) = sqrt((-6)^2 + 0) = 6

Length (2, 6) to (-4, 4) is sqrt((-4 - 2)^2 + (4 - 6)^2) = sqrt((-6)^2 + (-2)^2) = sqrt(36 + 4) = sqrt(40)  = 2sqrt(10) units

Length (-4, 6) to (-4, 4) is sqrt((-4 - (-4))^2 + (4 - 6)^2) = sqrt(0^2 + (-2)^2) = 2

So the length of the longest side is 2sqrt(10) units
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lara31 [8.8K]

Answer:

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Step-by-step explanation:

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