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hjlf
3 years ago
8

Work out an estimate for 304 × 9.96 ________ 0.51

Mathematics
1 answer:
vagabundo [1.1K]3 years ago
7 0
5936.94118 is the answer
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Please help I will mark brainiest ✅
TEA [102]

Answer:

y=-2x-3

the line is going downwards which makes the slop a negative value

Step-by-step explanation:

5 0
3 years ago
Lannister checks out 6 set of books from the library each set has the same number of books she reads 7 of the books and she has
fgiga [73]

Answer:

3

Step-by-step explanation:

Lannister checks out 6 sets of book

Each set had the same number of books

She reads 7 books and has 11 more to go

Therefore the number of books in each set can be calculated as follows

= 11+7

= 18

18/6

= 3

Hence there are 3 books in each set

6 0
3 years ago
The length of a rectangle is 7 ft longer than twice the width. If the perimeter is 92 ft find the length and width of the rectan
user100 [1]

Width of the rectangle is 13 ft and length of the rectangle is 33 ft

<u>Step-by-step explanation:</u>

Step 1:

Given perimeter of the rectangle = 92 ft. Let the width be x, then the length of the rectangle = 2x + 7. Use the formula for perimeter of a rectangle = 2(length + width) to find the dimensions.

92 = 2(2x + 7 + x) = 2(3x + 7) = 6x + 14

⇒ 92 = 6x + 14

⇒ 78 = 6x

⇒ x = 78/6

∴ x = 13 ft

⇒ Width of the rectangle = 13 ft

∴ Length of the rectangle = 2x + 7 = 26 + 7 = 33 ft

4 0
3 years ago
Please help me!!!
Vladimir79 [104]

Answer:

130

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Which matrix equation represents the system of equations?<br><br> {-x+ 2y = 0 <br> y= -2
Snowcat [4.5K]

We are given a system of equations,

\begin{cases}-x+2y=0\\y=-2\\ \end{cases}

This will translate into a 2x2 matrix of coefficients (because 2 equations and 2 unknowns),

\begin{bmatrix}-1&2\\0&1\\ \end{bmatrix}

The matrix will then be applied to the vector (lower dimensions on top),

\begin{bmatrix}x\\y\\ \end{bmatrix}

And the result vector will be whats on the other side of equals sign,

\begin{bmatrix}0\\-2\\ \end{bmatrix}

So to put everything together,

\begin{bmatrix}-1&2\\0&1\\ \end{bmatrix}\begin{bmatrix}x\\y\\ \end{bmatrix}=\begin{bmatrix}0\\-2\\ \end{bmatrix}

Hope this helps :)

6 0
3 years ago
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