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Leokris [45]
2 years ago
13

Have you searched Buzz Ch.at on playstore​

Computers and Technology
1 answer:
deff fn [24]2 years ago
3 0

Answer:

Reorder terms.

y=52x−1

Cancel the common factor of 22.Factor 22 out of −2-2.

y−4=5x2+52⋅(2(−1))y-4=5x2+52⋅(2(-1))

Cancel the common factor.

y−4=5x2+52⋅(2⋅−1)y-4=5x2+52⋅(2⋅-1)

Rewrite the expression.

y−4=5x2+5⋅−1y-4=5x2+5⋅-1

Multiply 55 by −1-1.

y−4=5x2−5

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What methods do phishing and spoofing scammers use?
Misha Larkins [42]

Answer:

please give me brainlist and follow

Explanation:

There are various phishing techniques used by attackers:

Installing a Trojan via a malicious email attachment or ad which will allow the intruder to exploit loopholes and obtain sensitive information. Spoofing the sender address in an email to appear as a reputable source and request sensitive information

4 0
2 years ago
Hi there are many annoying people in brainly making my head ache
iris [78.8K]

Answer:

Lol who is bothering you?

Explanation:

4 0
2 years ago
Read 2 more answers
Can u write a python program with this output
cestrela7 [59]

Answer:

Not exact, but it will help.

Explanation:

do something like this.

       print("""

       this program will help you plan your garden.

       First, we need some information about the dimensions you want.

       """)

       while True:

           try:

               response = int(input("Please enter the side length for your garden (in feet) : "))

           except ValueError:

               print("(!)Please Enter A Number(!)")

               print("")

               continue

           if str(response) == "":

               continue

           else

               length = int(response)

               break

repeat stuff like that up above for the rest, and then you can decide what to do with the variables and how they need to be multiplied for the output. Good luck!

                       

3 0
2 years ago
Output values below an amount Write a program that first gets a list of integers from input. The input begins with an integer in
Katarina [22]

The program that first gets a list of integers from input, gets the last value from the input, which indicates a threshold, and outputs all integers less than or equal to that last threshold value is:

import java.util.Scanner;

public class LabProgram {

 /* Define your methods here */

public static void main(String[] args) {

Scanner scnr = new Scanner(System.in);

int[] userValues = new int[20];

int upperThreshold;

int numVals;

numVals = scnr.nextInt();

GetUserValues(userValues, numVals, scnr);

upperThreshold = scnr.nextInt();

OutputIntsLessThanOrEqualToThreshold(userValues, numVals, upperThreshold);

}

}

Read more about java programming here:

brainly.com/question/26952414

#SPJ1

6 0
1 year ago
You are working for the census bureau and you need to write a program in C to do the following: a) count the number of people in
valina [46]

Answer:

See explaination

Explanation:

#include<iostream>

#include<stdio.h>

#include<conio.h>

#include<math.h>

using namespace std;

void main()

{

int RandomData[]={10,5,20,45,20,66,25,31,20,70}; //Random Data

int infant=0,young=0,middle=0,old=0,older=0; //To store count

int n,freq,count=0,high=0; //to store mode and other

double stdDev,mean,sum=0; //to store stdDev mean and sum

for(int i=0;i<(sizeof(RandomData)/sizeof(RandomData[0]));i++) //loop to count

{

if(RandomData[i]>0&&RandomData[i]<=18)

infant++;

else if(RandomData[i]>18&&RandomData[i]<=29)

young++;

else if(RandomData[i]>29&&RandomData[i]<=50)

middle++;

else if(RandomData[i]>50&&RandomData[i]<=69)

old++;

else if(RandomData[i]>69)

older++;

}

double first=0,sec=0; //to store result of stdDev formula first and second part

for(int i=0;i<(sizeof(RandomData)/sizeof(RandomData[0]));i++) //loop to calculate mean mode and stdDev

{

n=RandomData[i];

count=0;

for(int j=0;j<(sizeof(RandomData)/sizeof(RandomData[0]));j++)

{

if(n==RandomData[j])

count++;

}

if(high<count)

{

freq=RandomData[i];

high=count;

}

first+=(pow((RandomData[i]),2)/(sizeof(RandomData)/sizeof(RandomData[0])));

sec+=RandomData[i]/(sizeof(RandomData)/sizeof(RandomData[0]));

sum+=RandomData[i];

}

mean=sum/(sizeof(RandomData)/sizeof(RandomData[0]));

stdDev=sqrt(first-pow((sec),2));

/*------Printing Result-----*/

cout<<"\nCount:\nInfant: "<<infant<<"\nYoung: "<<young<<"\nMiddle: "<<middle;

cout<<"\nOld: "<<old<<"\nOlder: "<<older;

cout<<"\n\nMean: "<<mean<<"\nMode: "<<freq<<"\nStandard Deviation: "<<stdDev;

/*-----------XXXX-------------*/

getch();

}

8 0
2 years ago
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