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Leokris [45]
3 years ago
13

Have you searched Buzz Ch.at on playstore​

Computers and Technology
1 answer:
deff fn [24]3 years ago
3 0

Answer:

Reorder terms.

y=52x−1

Cancel the common factor of 22.Factor 22 out of −2-2.

y−4=5x2+52⋅(2(−1))y-4=5x2+52⋅(2(-1))

Cancel the common factor.

y−4=5x2+52⋅(2⋅−1)y-4=5x2+52⋅(2⋅-1)

Rewrite the expression.

y−4=5x2+5⋅−1y-4=5x2+5⋅-1

Multiply 55 by −1-1.

y−4=5x2−5

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A friend of Alex has gifted a movie collection, and Alex is excited to watch them all as quickly as possible. The duration of th
marishachu [46]

To find out the duration of alex's movies, you can use the code in C++ to make this calculation, where you will only need the number of movies and their duration, as well:

<h3>Writing code in C++:</h3>

<em>#include<bits/stdc++.h></em>

<em>using namespace std;</em>

<em>struct Movie {</em>

<em>   int timeBegin, duration, timeEnd;</em>

<em>   bool operator<(const Movie& another) const {</em>

<em>      return timeEnd < another.timeEnd;</em>

<em>   }</em>

<em>};</em>

<em>struct Festival {</em>

<em>   int count;</em>

<em>   vector<Movie> movies;</em>

<em>};</em>

<em>Festival* initialize(int timeBegin[], int duration[], int count) {</em>

<em>   Festival* filmFestival = new Festival;</em>

<em>   filmFestival->count = count;</em>

<em>   for (int i = 0; i < count; i++) {</em>

<em>      Movie temp;</em>

<em>      temp.timeBegin = timeBegin[i];</em>

<em>      temp.duration = duration[i];</em>

<em>      temp.timeEnd = timeBegin[i] + duration[i];</em>

<em>      filmFestival->movies.push_back(temp);</em>

<em>   }</em>

<em>   return filmFestival;</em>

<em>}</em>

<em>int solve(Festival* fest) {</em>

<em>   int res = 0;</em>

<em>   sort(fest->movies.begin(), fest->movies.end());</em>

<em>   int timeEnd = -1;</em>

<em>   for (int i = 0; i < fest->count; i++) {</em>

<em>      if (fest->movies[i].timeBegin >= timeEnd) {</em>

<em>         res++;</em>

<em>            timeEnd = fest->movies[i].timeEnd;</em>

<em>      }</em>

<em>   }</em>

<em>   return res;</em>

<em>}</em>

<em>int main(int argc, char *argv[]) {</em>

<em>int timeBegin[] = {1, 3, 0, 5, 5, 8, 8};</em>

<em>int duration[] = {3, 2, 2, 4, 3, 2, 3};</em>

<em>Festival * fest;</em>

<em>fest = initialize(timeBegin,duration, 7);</em>

<em>cout << solve(fest) << endl;</em>

<em>return 0;</em>

<em>}</em>

See more about C Code at brainly.com/question/17544466

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8 0
2 years ago
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Answer: i think 1, 3, and 4

Explanation:

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Option D discursive and planned is the correct option.

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Well, a discursive essay is a genre of writing that asks you to investigate a topic; gather, read and evaluate evidence; and present a position on your topic based on the evidence gathered.

What is an example of planned change?

The introduction of employee welfare measures, changes in the incentive system, introduction of new products and technologies, organizational restructuring, team building, enhancing employee communication, as well as technical expertise, fall under the category of Planned Change.

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Ackerman (1997) has distinguished between three types of change:

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Transitional – Seeks to achieve a known desired state that is different from the existing one. ...

Transformational – Is radical or second-order in nature.

Thus , option D is the correct option:

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brainly.com/question/25594630

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ExtremeBDS [4]
<span>Computer should perform more creative tasks than AI concepts. It designed some special purposes. But in future all the tasks are done by the single computer with the help of super speed. It should be looks like more than thousands of human being brain and should full fill all the artificial intelligent concepts. computer programs are followed some simple rules-based logic so pattern recognition is really little complex but in future it should be much better than now. The computer should be save more power . In some cases humans are flexible but computers are too accurate. But in situation based sometimes it should act like human flexibility. Now the mobile computers are dominated all others because of the people usage.</span>
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3 years ago
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