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Salsk061 [2.6K]
2 years ago
9

I need help in this with explanation ​

Mathematics
1 answer:
Ierofanga [76]2 years ago
7 0

Step-by-step explanation:

The figure is made up of an 8x8 square and 4 identical triangles with 8-ft bases and 4 ft in height. Each triangle has an area = (1/2)bh = (1/2)(8)(4) = 16 ft^2. The square part has an area of 8x8 = 64 ft^2. Therefore, the total area of the figure is

A = (area of square) + 4×(area of triangle)

= 64 ft^2 + 4(16ft^2)

= 128 sq ft

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Scheels received a shipment of 400 water bottles. 30% were yellow.
Amanda [17]
Answer:
There were 120 yellow water bottles in the shipment

Explanation:
Multiply 400 by 30% to find out how many water bottles came in yellow.

400 • .30 = 120

So, 120 were yellow.
6 0
3 years ago
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Find the value of x. Please help I will mark brainliest!!!!
Alisiya [41]

Answer:

x = 2

Step-by-step explanation:

The triangle is reflected across the circle meaning it should be the same on both sides.

6 0
2 years ago
Consider the equation below.
vaieri [72.5K]

Hello there

-y+2= -12(8y+8)

-y+2= -96y+96

-y+96y=96-2

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6 0
3 years ago
Solve the equation. f/29 = 28 f =
Vinvika [58]

Answer:

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Step-by-step explanation:

4 0
3 years ago
Of 1000 randomly selected cases of lung cancer, 823 resulted in death within 10 years.
Arada [10]

Answer:

a) 0.823 - 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.799

0.823 + 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.847

The 95% confidence interval would be given by (0.799;0.847)

b) n=\frac{0.823(1-0.823)}{(\frac{0.03}{1.96})^2}=621.79  

And rounded up we have that n=622

c) n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11  

And rounded up we have that n=1068

Step-by-step explanation:

Part a

\hat p=\frac{823}{1000}=0.823

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

If we replace the values obtained we got:

0.823 - 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.799

0.823 + 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.847

The 95% confidence interval would be given by (0.799;0.847)

Part b

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.03 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

And replacing into equation (b) the values from part a we got:

n=\frac{0.823(1-0.823)}{(\frac{0.03}{1.96})^2}=621.79  

And rounded up we have that n=622

Part c

n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11  

And rounded up we have that n=1068

5 0
3 years ago
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