Answer:
A. 10cm
B. 8 times
Step-by-step explanation:
The question is on volume of a conical container
Volume of a cone= 
where r is the radius of base and h is the height of the cone
Given diameter= 12 cm, thus radius r=12/2 =6 cm
h=10 cm
B.
If height and diameter were doubled
New height = 2×10 =20 cm
New diameter = 2×12 = 24, r=12 cm
volume = 
To find the number of times we divide new volume with the old volume
F(2) = 3(2)^2 + 2(2) + 4
= 3(4) + 4 + 4
= 12 + 8
f(2) = 20
f(a+h) = 3(a+h)^2 + 2(a+h) + 4
= 3(a^2 + 2ah + h^2) + 2a + 2h + 4
f(a+h) = 3a^2 + 6ah + 3h^2 + 2a + 2h + 4
Use substitution
x -4x - 7 = 2
-3x = 9, x = -3
Y = -4(-3) - 7
Y = 12 - 7, y = 5
Solution: x = -3, y = 5
Answer:
X = 5.9 (in degree mode)
Step-by-step explanation:
Do the following:
12(tan26) = X
Plugging this into a calculator, you will get:
X = 5.9 (in degree mode)
<span>Cone Volume = (<span>π<span> • r² •<span> h) ÷ 3
Original cone = (3.14 * 6^2 * 12) / 3
</span></span></span></span>
<span><span>Original cone = 452.16
</span>
cc
</span>Larger cone = <span>(3.14 * 6^2 * 18) / 3 = </span>
<span>
<span>
<span>
678.24
</span>
</span>
</span>
cc
Difference = <span>(678.24 -452.16) = </span>
<span>
<span>
<span>
226.08
</span>
</span>
</span>
cc
