Answer:
Step-by-step explanation:
Let
Y ----> field of vision that Yash's camera would need
we know that
Applying the law of sines
Solve for sin(Y)
![Y=sin^{-1}[\frac{sin(41\°)}{30}(25)]](https://tex.z-dn.net/?f=Y%3Dsin%5E%7B-1%7D%5B%5Cfrac%7Bsin%2841%5C%C2%B0%29%7D%7B30%7D%2825%29%5D)
Answer:
(-1,0)
step-by-step explanation:
(-6,3)
right 5
(-1,3)
down 3
(-1,0)
You can only cut down a integer number of trees. So you might look at a few integer values for x. As x get large the –x4 term dominates the expression for big losses. x = 0 is easy P(x) = -6. Without cutting any trees you have lost money Put x = 1 and you get for the terms in order -1 + 1 + 7 -1 -6 = 0. So P(x) crosses zero just before you cut the first tree. So you make a profit on only 1 tree. However when x=10 you are back into no profit. So compute a few values for x = 1,2,3,4,5,6,7,8,9.
To find the measure of the s angle que are going use the cosine law because we know all the sides of the triangule:
s² = r² + t² - 2*r*t * cos(S)
Then solve the equation
s² -r² - t² = -2*r*t * cos(S)
arccos ((s² -r² - t² /-2*r*t)) = S
arccos (((250)² -(850 cm)²-(940 cm)² /(-2* 850 cm*940 cm) = S
14.9 = S
round to the nearest 10th of a degree
15º = S
Answer:
Step-by-step explanation:
<h3><u>Given:</u></h3>
y = 12 cm
θ = 24°
Using trigonometric ratio, tan.
![\displaystyle \boxed{tan \theta = \frac{opposite}{adjacent} }\\\\tan \ 24 = \frac{x}{12} \\\\0.445 = \frac{x}{12} \\\\Multiply \ 12 \ to \ both \ sides\\\\0.445 \times 12 = x\\\\5.3 = x\\\\x = 5.3\\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cboxed%7Btan%20%5Ctheta%20%3D%20%5Cfrac%7Bopposite%7D%7Badjacent%7D%20%7D%5C%5C%5C%5Ctan%20%5C%2024%20%3D%20%5Cfrac%7Bx%7D%7B12%7D%20%5C%5C%5C%5C0.445%20%3D%20%5Cfrac%7Bx%7D%7B12%7D%20%5C%5C%5C%5CMultiply%20%5C%2012%20%5C%20to%20%5C%20both%20%5C%20sides%5C%5C%5C%5C0.445%20%5Ctimes%2012%20%3D%20x%5C%5C%5C%5C5.3%20%3D%20x%5C%5C%5C%5Cx%20%3D%205.3%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
