Question

The vertices of triangle PQR are listed below.

Answer 1

Answer:

A. 32 units

Step-by-step explanation:

First, we need to find all of the side lengths of triangle using distance formula:

• $Distance = \sqrt{(x2-x1)^2 + (y2-y1)^2}$

Now, we can calculate length of PQ, QR and PR sides by using their vertices and above formula:

• $PQ=\sqrt{(-13-(-5))^2+(-3-3)^2} =\sqrt{8^2+6^2}=10$
• $QR=\sqrt{(-5-(-13))^2+(-9-(-3))^2} =\sqrt{8^2+6^2}=10$
• $PR=\sqrt{(-5-(-5))^2+(-9-3)^2} =\sqrt{0^2+12^2}=12$

For perimeter we add up the length of all of its sides:

• $Perimeter = PQ +QR + PR=10+10+12=32$