The probabability of winning on at least 1 bet is equal to 1 less the probaility of not winning on either of the 6 bets.
The probability of not wining on any bet is independent of winning or not winning on any of the bets, so the combined probability is calculated as the product of each individual probability.
Each indivitual probability of not winning the is:
(number of not winning outcomes) / (number of possible outcomes) = 37 / 38.
Then, the combined probability of not winning the six times is: (1/38)*(37/38)*(37/38)*(37/38)*(37/38)*(37/38) =(37/38)^6
Therefore, the probability of winning at least one bet is:
= 1 - (37/38)^6 ≈ 1 - 0.973684 ≈ 0.03.
Answer: 0.03.
answer
long press i
Step-by-step explanation:
it's impossible to find out
The given case is an example of permutation problem because the order is important given that you should like the first two songs. The sample space is calculated through the equation,
15P2 = 210
Then, there are 3 songs that you liked, the probability of picking 2 out of them is,
3P2 = 6
Dividing the latter by the earlier result will give us an answer of 1/35.
40= 1,2,4,5,8,10,20,40
48= 1,2,3,4,6,8,12,16,24,48
the gcf is 8.
Answer: i can not answer bc there is no way to lol
Step-by-step explanation:
