HELP PLZZZZZ 1.)Determine the first five terms of the sequence A(n) = A(n − 1) + 13, where A(1) = 21.

Mathematics

1 answer:

pishuonlain [190]3 years ago

8 0

Use math. Way it is very helpful

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40•(420:x-37)=200 помогите решить уравнение

miv72 [106K]

40•(420:x-37)=200 означает $40(\frac{420}{x}-37)=200$

разделите обе стороны на 40

$\frac{420}{x}-37=5$

добавить 37 с обеих сторон

$\frac{420}{x}=42$

умножить обе стороны на х
420=42x

разделите обе стороны на 42
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12% of children are nearsighted, but this condition often is not detected until they go to kindergarten. A school district tests

Klio2033 [76]

Answer:

There is a 34.60% probability that 0 or 1 of them is nearsighted.

Step-by-step explanation:

For each children, there are only two possible outcomes. Either they are nearsighted, or they are not. This means that we can solve this problem using the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem, we have that:

12% of children are nearsighted. This means that $p = 0.12$ .

A school district tests all incoming kindergarteners' vision. In a class of 18 kindergarten students, what is the probability that 0 or 1 of them is nearsighted?

There are 18 students, so $n = 18$