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SVEN [57.7K]
4 years ago
7

Please help me :): with question 12-13

Mathematics
1 answer:
Schach [20]4 years ago
4 0

Answer:

Question 12 : Answer C

Question 13 : Answer C

Step-by-step explanation:

You might be interested in
A student takes a true-false test that has 12 questions and guesses randomly at each answer. Let X be the number of questions an
snow_lady [41]

Step-by-step answer:

assuming the true-false test have equal probabilities (each 0.5), we can use the binomial probability to calculate the sum of probabilities of getting 10, 11 or 12 questions correctly out of 12.

p=probability of success = 0.5

N=number of questions

x = number of correct answers

then

P(x) = C(N,x)(p^x)((1-p)^(N-x))

where C(N,x) = N!/(x!(N-x)!) = number of combinations of taking x objects out of N.

P(10) = C(12,10)(0.5^10)((1-0.5)^2) = 33/2048 = 0.01611

P(11) = C(12,11)(0.5^11)((1-0.5)^1)     =  3/1024 = 0.00293

P(12) = C(12,12)(0.5^12)((1-0.5)^0) =  1/4096 = 0.00024

for a total probability of 79/4096 = 0.01929

7 0
3 years ago
One car travels 390 miles in the same amount of time it takes a second car traveling 3 miles per hour slower than
taurus [48]
The first car is traveling at 65 miles per hour and the second car is traveling at 62 miles per hour.
Explanation:
390:x=372:(x-3)
372x=390(x-3)
372x=390x-1170
1170=390x-372x
1170/18=18x/18
x=65

x-3= 65-3=62
6 0
3 years ago
URGENT PLEASE, I don't know how to do this
zysi [14]

Answer:

20x +1

Step-by-step explanation:

do the exponite first. 4X4=16. then add on 4x, 16x+4x=20x, then add on 1

7 0
3 years ago
A football team has a probability of .75 of winning when playing any of the other four teams in its conference. If the games are
Alexeev081 [22]

Answer:

0.3164 = 31.64% probability the team wins all its conference games

Step-by-step explanation:

For each conference game, there are only two possible outcomes. Either the team wins it, or they lose. The probability of winning a game is independent of any other game. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

A football team has a probability of .75 of winning when playing any of the other four teams in its conference.

The probability means that p = 0.75, and four games means that n = 4

If the games are independent, what is the probability the team wins all its conference games?

This is P(X = 4). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 4) = C_{4,4}.(0.75)^{4}.(0.25)^{0} = 0.3164

0.3164 = 31.64% probability the team wins all its conference games

4 0
3 years ago
The art clup has 18 members.Each member must contribute 12.80 every month for supplies.On the first of the month 11 members paid
klio [65]

18×12.80=230.40 (class total)
11×12.80=140.80 (1st day)
230.40-140.80=89.60 (amount paid on 2nd day)

Other way
18-11=7
7×12.80=89.6

8 0
3 years ago
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