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3 years ago

A bag contains 6 one-dollar coins and 4 two-dollar coins. Three coins are taken at random without replacement.

Mathematics

1 answer:

IgorLugansk [536]3 years ago

3 0

The answer is b why because I had did it on the test and I had got it right HOPEFULLY IT HELPS

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A yard of fabric costs 22.99 how much will 2 feet costs

marshall27 [118]

$\frac{22.99}{3ft} = \frac{d}{2ft} \\ \\ d=15.33$

7 0

3 years ago

Read 2 more answers

Enter the correct answer in the box. solve the equation x2 − 16x 54 = 0 by completing the square. fill in the values of a and b

poizon [28]

The roots of the given polynomials exist $x=8+\sqrt{10}$ , and $x=8-\sqrt{10}$ .

<h3>What is the formula of the quadratic equation?</h3>

For a quadratic equation of the form $a x^{2}+b x+c=0$ the solutions are

$x_{1,2}=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Therefore by using the formula we have

$x^{2}-16 x+54=0$$

Let, a = 1, b = -16 and c = 54

Substitute the values in the above equation, and we get

$x_{1,2}=\frac{-(-16) \pm \sqrt{(-16)^{2}-4 \cdot 1 \cdot 54}}{2 \cdot 1}$$

simplifying the equation, we get

$$&x_{1,2}=\frac{-(-16) \pm 2 \sqrt{10}}{2 \cdot 1} \\$

$$&x_{1}=\frac{-(-16)+2 \sqrt{10}}{2 \cdot 1}, x_{2}=\frac{-(-16)-2 \sqrt{10}}{2 \cdot 1} \\$

$$&x=8+\sqrt{10}, x=8-\sqrt{10}$

Therefore, the roots of the given polynomials are $x=8+\sqrt{10}$ , and

$x=8-\sqrt{10}$ .

To learn more about quadratic equations refer to:

brainly.com/question/1214333

#SPJ4

3 0

1 year ago

Read 2 more answers

(1) [6pts] Let R be the relation {(0, 1), (1, 1), (1, 2), (2, 0), (2, 2), (3, 0)} defined on the set {0, 1, 2, 3}. Find the foll

goldenfox [79]

Answer:

Following are the solution to the given points:

Step-by-step explanation:

In point 1:

The Reflexive closure:

Relationship R reflexive closure becomes achieved with both the addition(a,a) to R Therefore, (a,a) is $(0,0),(1,1),(2,2) \ and \ (3,3)$

Thus, the reflexive closure: $R={(0,0),(0,1),(1,1),(1,2),(2,0),(2,2),(3,0), (3,3)}$

In point 2:

The Symmetric closure:

R relation symmetrically closes by adding(b,a) to R for each (a,b) of R Therefore, here (b,a) is: $(0,1),(0,2)\ and \ (0,3)$

Thus, the Symmetrical closure:

$R={(0,1),(0,2),(0,3)(1,0),(1,1)(1,2),(2,0),(2,2),(3,0), (3,3)}$

8 0

3 years ago

Anyone plz show how to work it out step by step.

In-s [12.5K]

Answer:

168cm^3

Step-by-step explanation:

Q to P is going to be 3cm. it is identical to the length T to U.

R to T , W to Q, S to U is going to be identical to P to V. P to V has been identified as 12 cm.

in the middle of the shape, there are 4 identical triangles. the height time length will give us the area of that one shape:

e.g for shape P to V to W to Q and back to P is one rectangle. the length is 12 cm and the width is 3 cm.

12 x 3= 36

36cm^3 is one rectangles surface area, we have 4 identical triangles that means we need to times 36 by 4.

so 36x4=144.

now on the left and right side, we have two squares. on the right, we have T to U to V to W back to T this has the height of 3 width of 4 then we do 3 X 4 which is 12, we times it by 2 because we have two identical squares.

12 X 2=24

finally we add 24 and 144 = 168cm^3.

hope this helps :)

6 0

3 years ago

FAST HELP PLEASE AWNSER

Lera25 [3.4K]

So the simplified version would be,

${3p}^{4}$

The degrees I'm unaware of...

3 0

3 years ago