If sin ø = 1/3, what are the values of cos ø and tan ø?
1 answer:
Step-by-step explanation:
SinA=1/3=p/h
p=1,h=3,and b=?
Using Pythagoras Theorem,
b=√3^2-1^2
b=√9-1
b=√8=2√2
Now,
CosA=b/h=2√2/3
TanA=p/b=1/2√2
There is no phi in my keypad so I use A angle instead of phi.Adjust it.
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