This is a problem of conditional probability that can be calculated by the formula:
P(B | A) = P(A ∩ B) / P(A)
We know that:
- between 1 and 50 there are 41 two-digit numbers, therefore
P(A) = 41/50 = 0.82
- between 1 and 50 there are 8 multiples of six, therefore
P(B) = 8/50 = 0.16
- <span>between 1 and 50 there are 7 two-digits mutiples of six, therefore
P(A ∩ B) = 7/50 = 0.14
Now, we can calculate:
</span>P(B | A) = P(A <span>∩ B) / P(A)
= 0.14 / 0.82
= 0.17
Therefore, the probability of getting a multiple of 6 if we draw a two-digit number is 17%.</span>
The second one because look at what everything’s it adds up to add it all up and you get the second one
Answer:
Total cost of equipment was $612. The remaining amount was spent on uniforms.
To find out how many uniforms were purchased,
Total cost of uniforms
=$912-$612
=$300
Number of uniforms purchased
=
$
300
$
25
=12
Step-by-step explanation:
Answer:
(-4,3) it is x axis -4 and y axis 3
Answer:
remainder = 32
Step-by-step explanation:
Using synthetic division with divisor (x - 2) , that is h = 2
There is no x³ term so include zero as its coefficient in the table
2 | 3 0 - 3 2 - 8
↓ 6 12 18 40
------------------------------
3 6 9 20 32 ← remainder
