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gtnhenbr [62]
3 years ago
11

Using the order of operation which should be done first to evaluate 6+(-5-7)/2-8(3)?

Mathematics
1 answer:
valentinak56 [21]3 years ago
6 0

Answer:

\frac{3}{11}

Step-by-step explanation:

=> \frac{6+(-5-7)}{2-8(3)}

=> \frac{6+(-12)}{2-24}

=> \frac{6-12}{-22}

=> \frac{-6}{-22}

=> \frac{3}{11}

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Read 2 more answers
Can someone please write this as a single logarithm and show work please and thank you
Mazyrski [523]

Answer:  

log_b(w^3y^4)

Step-by-step explanation:

To write the expression as a single logarithm, or condense it, use the properties of logarithms.  

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So, in this case, we can move the 3 and the 4 inside the logarithms as exponents. Apply this property as seen below:

3log_bw+4log_by\\=log_bw^3+log_by^4

2) The product property of logarithms states that log_axy = log_ax+log_ay. In other words, the logarithm of a product is equal to the sum of the logarithms of its factors. So, in this case, write the expression as a single logarithm by taking the log (keep the same base) of the product of w^3 and y^4. Apply the property as seen below and find the final answer.  

log_bw^3+log_by^4\\=log_b(w^3y^4)

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