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2 years ago

Using the order of operation which should be done first to evaluate 6+(-5-7)/2-8(3)?

Mathematics

1 answer:

valentinak56 [21]2 years ago

6 0

Answer:

$\frac{3}{11}$

Step-by-step explanation:

=> $\frac{6+(-5-7)}{2-8(3)}$

=> $\frac{6+(-12)}{2-24}$

=> $\frac{6-12}{-22}$

=> $\frac{-6}{-22}$

=> $\frac{3}{11}$

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Solving by elimination 5x+2y= -3 3x+3y=9 please help me solve x and y

-Dominant- [34]

1) -3(5x+2y=-3)⇒ -15x-6y=9
⇒ -9x=27
2(3x+3y=9)⇒ 6x+6y=18

2) -9x/-9=27/-9 ⇒ x=-3

3) 3(-3)+3y=9⇒ -9+9+3y=9+9⇒ 3y/3=18/3⇒ y=6

Answer: (-3,6)

Reasoning:
Step 1) In order to eliminate, first I had to multiple the first equation by -3 and the second by 2 so that when combining the equations y would cancel each other out so that I could solve for x. Note: There are many combinations as to how you could multiple the equations so that either the x or y would cancel out.

Step 2) Once y is eliminated, solve for x.

Step 3) Now plug x back into one of the original equations and solve for y. Note: Plug x back into one of the original equations, not the equations that were changed by multiplication,

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