If f(x) = x2 is vertically stretched by a factor of 4 to g(x) and reflected over the x-axis, what is the equation for g(x)?

Mathematics

1 answer:

alexdok [17]2 years ago

8 0

Step-by-step explanation:

integral fx = gx, gx = fx

gx = -4x2

variable of x2 = replace to left side it mean we got minus when Variable replace to left it mean minus

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Limit of x^2-81/x+9 As x goes toward -9

Semmy [17]

Hello,

Use the factoration

a^2 - b^2 = (a - b)(a + b)

Then,

x^2 - 81 = x^2 - 9^2

x^2 - 9^2 = ( x - 9).(x + 9)

Then,

Lim (x^2- 81) /(x+9)

= Lim (x -9)(x+9)/(x+9)

Simplity x + 9

Lim (x -9)

Now replace x = -9

Lim ( -9 -9)

Lim -18 = -18
_______________

The second method without using factorization would be to calculate the limit by the hospital rule.

Lim f(x)/g(x) = lim f(x)'/g(x)'

Where,

f(x)' and g(x)' are the derivates.

Let f(x) = x^2 -81

f(x)' = 2x + 0
f(x)' = 2x

Let g(x) = x +9

g(x)' = 1 + 0
g(x)' = 1

Then the Lim stay:

Lim (x^2 -81)/(x+9) = Lim 2x /1

Now replace x = -9

Lim 2×-9 = Lim -18

= -18

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3 years ago

If f(x) = x2 is vertically stretched by a factor of 4 to g(x) and reflected over the x-axis, what is the equation for g(x)?​

If f(x) = x2 is vertically stretched by a factor of 4 to g(x) and reflected over the x-axis, what is the equation for g(x)?