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Luden [163]
3 years ago
11

Name:

Mathematics
1 answer:
tino4ka555 [31]3 years ago
3 0

Answer: 4

Step-by-step explanation:

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Describe in writing how 7/3 compares to 2 1/3
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7/3 IS an improper fraction 2 1/3 is a mixed number
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Can someone please help ? ❤️
faust18 [17]

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B

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elena55 [62]

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Step-by-step explanation:

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3 years ago
Find the permeter of a quadrilateral with vertices at C (2,4), D(1,1), E(5,0), and F(3,4). Round your answer to the nearest hund
denpristay [2]

Answer:

12.76

Step-by-step explanation:

This is much easier to solve if you draw it out on a graph. The perimeter is the sum of all the sides. I used the Pythagorean theorem to find the hypotenuse.

{a}^{2}  +  {b}^{2}  =  {c}^{2}  \\ c =  \sqrt{ {a}^{2} +  {b}^{2}  }

dc =  \sqrt{ {3}^{2}  +  {1}^{2} }  =  \sqrt{10}  \\  cf = 1 \\ fe =  \sqrt{ {4}^{2}  +  {2}^{2} }  =  \sqrt{20}  \\ de =  \sqrt{ {1}^{2} +  {4}^{2}  }  =  \sqrt{17}  \\  \sqrt{10}  + 1 +  \sqrt{20}  +  \sqrt{17}  = 12.76

7 0
3 years ago
A spinner has 12 equal sectors. 4 sectors are coloured red, 3 are coloured blue, and 5 are coloured yellow. The pointer on the s
vodomira [7]

Answer:

3.70% probability of the pointer landing on red each time

Step-by-step explanation:

For each time that the pointer is spun, there are only two possible outcomes. Either it lands on red, or it does not. The probability that it lands on red on a spin is independent of other spins. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

12 sections, of which 4 are red.

This means that p = \frac{4}{12} = 0.3333

The pointer on the spinner is spun 3 times.

This means that n = 3

What is the probability of the pointer landing on red each time?

This is P(X = 3).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 3) = C_{3,3}.(0.3333)^{3}.(0.6667)^{0} = 0.0370

3.70% probability of the pointer landing on red each time

3 0
3 years ago
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