Simplify (3х – 5) – (5х + 1). (1 point) а ob - 2x - 6 Ос 2x - 6 od
1 answer:
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Answer:
Minimum < Q1 < Median < Q3< Maximum
Step-by-step explanation:
Given
Minimum, Median, Maximum, Q3 and Q1
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Required
Order from least to greatest
In a dataset, the range is:
This implies that, the minimum is the least and the maximum is the highest of the dataset
So, we have:
Minimum < < < < Maximum
The median is the middle item; So, the above becomes
Minimum < < Median < < Maximum
In a dataset, the IQR is:
This implies that:
So, we have:
Minimum < Q1 < Median < Q3< Maximum
