<span>v = 4/3*pi*r^3
derivating both sides with respect to t
dv/dt = 4*pi*r^2*dr/dt
when d = 1.7, r = 0.85, and dv/dt = 2:
2 = 4*pi*(0.85)^2*dr/dt
thus
dr/dt = 1/(2pi*(0.85)^2)
=1/(2*3.14*0.85^2)
=0.22</span><span />
Answer:
x=4 orx=- 8
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
4
x
=
−
x
2
+
32
Step 2: Subtract -x^2+32 from both sides.
4
x
−
(
−
x
2
+
32
)
=
−
x
2
+
32
−
(
−
x
2
+
32
)
x
2
+
4
x
−
32
=
0
Step 3: Factor left side of equation.
(
x
−
4
)
(
x
+
8
)
=
0
Step 4: Set factors equal to 0.
x
−
4
=
0
or
x
+
8
=
0
x
=
4
or
x
=
−
8
The new parking lot must hold twice as many cars as the previous parking lot. The previous parking lot could hold 56 cars. So this means the new parking lot must hold 2 x 56 = 112 cars
Let y represent the number of cars in each row, and x be the number of total rows in the parking lot. Since the number of cars in each row must be 6 less than the number of rows, we can write the equation as:
y = x - 6 (1)
The product of cars in each row and the number of rows will give the total number of cars. So we can write the equation as:
xy = 112 (2)
Using the above two equations, the civil engineer can find the number of rows he should include in the new parking lot.
Using the value of y from equation 1 to 2, we get:
x(x - 6) = 112 (3)
This equation is only in terms of x, i.e. the number of rows and can be directly solved to find the number of rows that must in new parking lot.
Answer:
work is shown and pictured
Answer:
33.1
Step-by-step explanation:
First you need to find the area of the circle. The radius is 10 which means that the area is 314. Since a circle has 360 degrees, and the shaded area is 38 degrees, you need to divide 314 by 360 which is 0.87. Then multiply by 38 because the shaded sector is 38. 0.87 x 38 = 33.1.
That is the answer.
