A. 3a b. a^3 c. 4x d. 3pq e. 7^ef f. zxy^1
The solution of the given equation is -6 and 1.
<h3>What is Quadratic Equation?</h3>
A quadratic equation is an algebraic equation of the second degree in x. The quadratic equation in its standard form is ax² + bx + c = 0, where a and b are the coefficients, x is the variable, and c is the constant term.
Here, given equation:
(x+2)(x+3) = 12
x(x+3)+2(x+3) = 12
x² + 3x + 2x + 6 = 12
x² + 5x + 6 - 12 = 0
x² + 5x - 6 = 0
x² + 6x - x - 6 = 0
x(x+6) -1(x+6) = 0
(x+6)(x-1) = 0
Now, x + 6 = 0 or x - 1 = 0
x = -6 or x = 1
Thus, the solution of the given equation is -6 and 1.
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Answer:
(f o g)(4)=27
Step-by-step explanation:
(f o g)(4)=2x+5
f(g(4))=2x+5
f(4²-2(4)+3)=2x+5
f(16-8+3)=2x+5
f(8+3)=2x+5
f(11)=2x+5
f(11)=2(11)+5
f(11)=22+5
f(11)=27
Therefore, (f o g)(4)=27
Answer:
1953125
Step-by-step explanation:
