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Zolol [24]
2 years ago
14

Please hurry, Find the sum of the first 10 terms in the series:

Mathematics
2 answers:
Mariana [72]2 years ago
6 0

Answer:

44,286

Step-by-step explanation:

The rule is multiplying by -3.

The sequence goes -3, 9, -27, 81, -243, 729, -2187, 6561, -19683, 59049

Add all of those up and you get 44,286

sdas [7]2 years ago
4 0

Answer:

\huge \boxed{\mathrm{\bold{C.} \ 44286}}

Step-by-step explanation:

-3, 9, -27, 81...

The common ratio can be found by taking the quotient of a term in the sequence and the previous term.

\displaystyle \frac{9}{-3} =-3

The common ratio is -3.

A term in the sequence multiplies itself by -3 to get the next term.

The nth term for the sequence is : a_n=(-3)^n

The first 10 terms of the sequence are :

-3, 9, -27, 81, -243, 729, -2187, 6561, -19683, 59049

Adding these 10 terms :

-3 + 9 + -27 + 81 + -243 + 729 + -2187 + 6561 + -19683 + 59049

⇒ 44286

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High school football team had the best game of the season they scored eight touchdowns (seven points each) and three field goals
Alla [95]

Answer:

65 points in all

Step-by-step explanation:

3 x 3 = 9

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6 0
3 years ago
A plane takes off from an airport and flies at a speed of 400km/h on a course of 120° for 2 hours. the plane then changes its co
butalik [34]

Answer:

Distance from the airport = 894.43 km

Step-by-step explanation:

Displacement and Velocity

The velocity of an object assumed as constant in time can be computed as

\displaystyle \vec{v}=\frac{\vec{x}}{t}

Where \vec x is the displacement. Both the velocity and displacement are vectors. The displacement can be computed from the above relation as

\displaystyle \vec{x}=\vec{v}.t

The plane goes at 400 Km/h on a course of 120° for 2 hours. We can compute the components of the velocity as

\displaystyle \vec{v_1}=

\displaystyle \vec{v_1}=\ km/h

The displacement of the plane in 2 hours is

\displaystyle \vec{x_1}=\vec{v_1}.t_1=.(2)

\displaystyle \vec{x_1}=km

Now the plane keeps the same speed but now its course is 210° for 1 hour. The components of the velocity are

\displaystyle \vec{v_2}=

\displaystyle \vec{v_2}=km/h

The displacement in 1 hour is

\displaystyle \vec{x_2}=\vec{v_2}.t_2=.(1)

\displaystyle \vec{x_2}=km

The total displacement is the vector sum of both

\displaystyle \vec{x_t}=\vec{x_1}+\vec{x_2}=+

\displaystyle \vec{x_t}=km

\displaystyle \vec{x_t}=

The distance from the airport is the module of the displacement:

\displaystyle |\vec{x_t}|=\sqrt{(-746.41)^2+492.82^2}

\displaystyle |\vec{x_t}|=894.43\ km

8 0
3 years ago
What is the area of a parallelogram with a base of 38 meters and a height of 12 meters?
8090 [49]

For this case we have by definition that the area of a parallelogram is given by:

A = b * h

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b: It's the base

h: It's the height

According to the data we have:

b = 38\ m\\h = 12 \ m

Substituting in the formula:

A = 38 * 12\\A = 456

The area of the parallelogram is A = 456 \ m ^ 2

Answer:

A = 456 \ m ^ 2

4 0
3 years ago
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