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3241004551 [841]

3 years ago

13

John earns $24,008 per year and claims 3 exemptions. His local tax rate is 5.5%. The amount for each exemption is $800. How much

local income tax should be withheld from his monthly earnings? (Round your answer to the nearest cent.)

2 answers:

stepladder [879]3 years ago

7 0

Answer:

The correct answer is $99,04

Step-by-step explanation:

Step 1: We must first deduct the total amount of exemptions John claims per year from his annual income.

$24008 - ($800 * 3)= $21608

The 5.5% tax must be applied to the amount of $21608.

Step 2: We now calculate the tax on the amount of $21608 and divide it by 12 months to get the monthly amount that must be deducted from your taxable earnings.

$21608 * $\frac{5,5}{100}$ = $1188,44

$\frac{1188,44}{12}$ = $99,04

The amount to be deducted per month in taxes is $99.04.

Have a nice day!

algol [13]3 years ago

6 0

Johns monthly earnings will be $ 576,192

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Which table represents the graph of a logarithmic function in the form y=log3x when b>1?

alex41 [277]

Answer:

<u><em>The satisfied table of the given function</em></u> $y = log_{b} (x)$ <u><em></em></u>

<em>x 1/8 1/4 1/2 1 2</em>

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<em></em>

Step-by-step explanation:

<u><em>Explanation</em></u> :-

Given logarithmic function $y = log_{b} (x)$ if b >1

Given first table

i)

put x = $\frac{1}{8}$ given b > 1 so we can choose b = 2

$y = log_{2} (\frac{1}{8} )$

$y = log_{2} (2^{-3} )$

we will apply logarithmic formula

log x ⁿ = n log (x)

$y = log_{2} (2^{-3} ) = -3 log_{2} (2) = -3 (1) = -3$

<em>y = -3</em>

<em>ii)</em>

<em>put x = </em> $\frac{1}{4}$ <em> given b > 1 so we can choose b = 2</em>

<em></em> $y = log_{2} (\frac{1}{4} )$ <em></em>

<em></em> $y = log_{2} (2^{-2} )$ <em></em>

we will apply logarithmic formula

log x ⁿ = n log (x)

$y = log_{2} (2^{-2} ) = -2 log_{2} (2) = -2 (1) = -2$

<em>y = -2</em>

<em>iii) </em>

<em>put x = </em> $\frac{1}{2}$ <em> given b > 1 so we can choose b = 2</em>

<em></em> $y = log_{2} (\frac{1}{2} )$ <em></em>

$y = log_{2} (2^{-1} )$

<em>we will apply logarithmic formula </em>

<em>log x ⁿ = n log (x)</em>

$y = log_{2} (2^{-1} ) = -1 log_{2} (2) = - (1) = -1$

<em>y = -1</em>

<em>iv) </em>

<em>put x = 1 given b > 1 so we can choose b = 2</em>

<em></em> $y = log_{2} (1 )$ <em> = 0</em>

<em>y = 0</em>

<em>v) </em>

<em>put x = </em> $2$ <em> given b > 1 so we can choose b = 2</em>

$y = log_{2} (2 )$

<em>y = 1</em>

<em></em>

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<u><em>The satisfied table of the given function</em></u>

<em>x 1/8 1/4 1/2 1 2</em>

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Step-by-step explanation:

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