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AURORKA [14]
4 years ago
11

Of the 27 players trying out for the school basketball team, 8 are more than 6 feet tall and 7 have good aim. What is the probab

ility that the coach would randomly pick a player over 6 feet tall or a player with a good aim? Assume that no players over 6 feet tall have good aim. A. 7/15 B. 6/15 C. 7/9 D. 5/9
Mathematics
1 answer:
Komok [63]4 years ago
5 0
Of the 27 players trying out for the school basketball team, 8 are more than 6 feet tall and 7 have good aim. What is the probability that the coach would randomly pick a player over 6 feet tall or a player with a good aim? Assume that no players over 6 feet tall have good aim. A. 7/15 B. 6/15 C. 7/9 D. 5/9

The Answer Is

--------5/9--------
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What is-simplify 3ab x 2ac x 5b?
Pie
Being simplified the answer is 30a^2b^3x^2.
7 0
3 years ago
A computer randomly selects a number from the given set. {2, 4, 6, 9, 16, 44, 51, 60, 78} What is the probability that a number
nekit [7.7K]
You would find the probability of getting an answer less than 10 by counting all of the possible outcomes, or numbers that are less than 10 and compare them to the total number of possible outcomes, or the total number of numbers. You would write the ratio of predicted outcomes to total possibilities.

The answer would be 4/9.
3 0
3 years ago
Sasha buys two ribbons of equal length. She cuts 9 pieces of the same length, L, from the first ribbon and finds that 5 inches a
nikitadnepr [17]

Answer:

50 inches.

Step-by-step explanation:

Let the length of the each ribbon was x.

Now, she cuts 9 pieces of same length L which means total length is 9L.

Now, doing the same she was left with 5 inches of ribbon. Hence, we have

[tex[9L+5=x.....(1)[/tex]

Similarly, we can write a equation for the second situation.

2L+40=x......(2)

From equation 1 and 2,

9L+5=2L+40\\\\7L=35\\\\L=5

Plugging this value in equation 1,

9(5)+5=x\\\\x=45+5\\x=50

Therefore, the length of each ribbon when she bought them was 50 inches.

3 0
4 years ago
Anyone know how to solve this?
yuradex [85]

Answer:

<h2>\frac{16}{25}</h2>

Step-by-step explanation:

<h3>( -  \frac{4}{5})^{2}</h3><h3>{( - 1)}^{2}  \frac{ {4}^{2} }{ {5}^{2} }</h3><h3>1 \frac{ {4}^{2} }{ {5}^{2} }</h3><h3>\frac{ {4}^{2} }{ {5}^{2} }</h3><h3>\frac{16}{25}</h3><h3>Hope it is helpful....</h3>
5 0
3 years ago
Consider the quadratic function f(x) = 2x2 – 8x – 10. The x-component of the vertex is . The y-component of the vertex is . The
mr_godi [17]
F(x) = 2x² - 8x - 10.
This is a parabola open upward (since a>0) with an axis of symmetry = -b/2a:
a) axis of symmetry: x = -(-8)/(2*2) = 8/4 = 2. Then x = 2, which is the x component of the vertex
b) for x =  2, f(x) = f(2) = - 18 (component of y of the vertex)
c) VERTEX(2, - 18)
d) DISCRIMINENT: b² - 4.a.c = 64 - 4*2*(-10) = 144
8 0
3 years ago
Read 2 more answers
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