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lilavasa [31]
3 years ago
12

A group of friends would like to play bowling. They would have to pay $4.45 for a game or pay $28.95 per hour. Under which circu

mstance would they have to pay for the hourly cost? Explain.
(This was on one of my assignments and it was meant to be a hard question but isn't it common sense to say if they stayed for an hour? But I'm pretty sure that is not the answer. They are probably looking for which would be a better cost but I'm not sure)
Mathematics
1 answer:
andrew11 [14]3 years ago
6 0
They would have to pay the hourly cost if they played around 7 games because 7 games would equal to the cost of one hour.
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Explain how the graph of y=|x+1|-2 will differ from the graph of y=|x|.
Natali5045456 [20]

\bf ~~~~~~~~~~~~\textit{function transformations}\\\\\\f(x)=  A(  Bx+  C)+  D\\\\~~~~y=  A(  Bx+  C)+  D\\\\f(x)=  A\sqrt{  Bx+  C}+  D\\\\f(x)=  A(\mathbb{R})^{  Bx+  C}+  D\\\\f(x)=  A sin\left( B x+  C  \right)+  D\\\\--------------------\\\\\bullet \textit{ stretches or shrinks horizontally by  }   A\cdot   B\\\\\bullet \textit{ flips it upside-down if }  A\textit{ is negative}

\bf ~~~~~~\textit{reflection over the x-axis}\\\\\bullet \textit{ flips it sideways if }  B\textit{ is negative}\\~~~~~~\textit{reflection over the y-axis}\\\\\bullet \textit{ horizontal shift by }\frac{  C}{  B}\\~~~~~~if\ \frac{  C}{  B}\textit{ is negative, to the right}

\bf ~~~~~~if\ \frac{  C}{  B}\textit{ is positive, to the left}\\\\\bullet \textit{ vertical shift by }  D\\~~~~~~if\   D\textit{ is negative, downwards}\\\\~~~~~~if\   D\textit{ is positive, upwards}\\\\\bullet \textit{ period of }\frac{2\pi }{  B}

with that template in mind,

\bf y=\stackrel{A}{1}|\stackrel{B}{1}x\stackrel{C}{+1}|\stackrel{D}{-2}

so is really just |x| but shifted some,

C/B = 1/1 = +1, horizontally to the right by 1 unit.

D = -2, vertically downwards by 2 units.

3 0
3 years ago
???!!???????????????????
natita [175]

The solution's something you can really easily pick up, I promise.

The solution is simply the point where the two lines connect.

In this case, it's (2,5). (x,y)

Hope this helped!

(Khan Academy is a great resource.)

3 0
3 years ago
List the elements of the set of all letters in the word "FOUR"
aleksley [76]

Answer:

{F, O, U, R} in the word 'FOUR'

3 0
3 years ago
Question 6 (Essay Worth 5 points) Part A: Find a rational number that is between 5.2 and 5.5. Explain why it is rational. (2 poi
insens350 [35]
Rational between 5.2 and 5.5

5.2 × 10/10 = 52/10
5.5 × 10/10 = 55/10
rational no. b/w them is 53/10 = 5.3

rational because it is in p/q form where q is not zero and p and q are integers.



irrational.no. b/w 5.2 and 5.5


5.20102030405060708090.......

irrational.no because it is non terminating and non recurring
6 0
3 years ago
5.
Delicious77 [7]

You can solve for the velocity and position functions by integrating using the fundamental theorem of calculus:

<em>a(t)</em> = 40 ft/s²

<em>v(t)</em> = <em>v </em>(0) + ∫₀ᵗ <em>a(u)</em> d<em>u</em>

<em>v(t)</em> = -20 ft/s + ∫₀ᵗ (40 ft/s²) d<em>u</em>

<em>v(t)</em> = -20 ft/s + (40 ft/s²) <em>t</em>

<em />

<em>s(t)</em> = <em>s </em>(0) + ∫₀ᵗ <em>v(u)</em> d<em>u</em>

<em>s(t)</em> = 10 ft + ∫₀ᵗ (-20 ft/s + (40 ft/s²) <em>u</em> ) d<em>u</em>

<em>s(t)</em> = 10 ft + (-20 ft/s) <em>t</em> + 1/2 (40 ft/s²) <em>t</em> ²

<em>s(t)</em> = 10 ft - (20 ft/s) <em>t</em> + (20 ft/s²) <em>t</em> ²

6 0
2 years ago
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