with that template in mind,
so is really just |x| but shifted some,
C/B = 1/1 = +1, horizontally to the right by 1 unit.
D = -2, vertically downwards by 2 units.
The solution's something you can really easily pick up, I promise.
The solution is simply the point where the two lines connect.
In this case, it's (2,5). (x,y)
Hope this helped!
(Khan Academy is a great resource.)
Answer:
{F, O, U, R} in the word 'FOUR'
Rational between 5.2 and 5.5
5.2 × 10/10 = 52/10
5.5 × 10/10 = 55/10
rational no. b/w them is 53/10 = 5.3
rational because it is in p/q form where q is not zero and p and q are integers.
irrational.no. b/w 5.2 and 5.5
5.20102030405060708090.......
irrational.no because it is non terminating and non recurring
You can solve for the velocity and position functions by integrating using the fundamental theorem of calculus:
<em>a(t)</em> = 40 ft/s²
<em>v(t)</em> = <em>v </em>(0) + ∫₀ᵗ <em>a(u)</em> d<em>u</em>
<em>v(t)</em> = -20 ft/s + ∫₀ᵗ (40 ft/s²) d<em>u</em>
<em>v(t)</em> = -20 ft/s + (40 ft/s²) <em>t</em>
<em />
<em>s(t)</em> = <em>s </em>(0) + ∫₀ᵗ <em>v(u)</em> d<em>u</em>
<em>s(t)</em> = 10 ft + ∫₀ᵗ (-20 ft/s + (40 ft/s²) <em>u</em> ) d<em>u</em>
<em>s(t)</em> = 10 ft + (-20 ft/s) <em>t</em> + 1/2 (40 ft/s²) <em>t</em> ²
<em>s(t)</em> = 10 ft - (20 ft/s) <em>t</em> + (20 ft/s²) <em>t</em> ²
