Question

In a certain lottery, five different numbers between 1 and 35 inclusive are drawn. These are the winning numbers. To win the lottery, a person must select the correct 5 numbers in the same order in which they were drawn. What is the probability of winning

Answer 1

Answer:

$Pr =\frac{1}{38955840}$

Step-by-step explanation:

Given

$n = 35$ ---- 1 to 35

$r = 5$ -- selection

Required

The probability of winning

The probability of getting the first number correctly is:

$P(1) = \frac{1}{35}$

At this point, the remaining numbers are 34

So, the second selection has the following probability

$P(2) = \frac{1}{34}$

Following the above sequence, we have:

$P(3) = \frac{1}{33}$

$P(4) = \frac{1}{32}$

$P(5) = \frac{1}{31}$

So, the required probability is:

$Pr =P(1) * P(2) * P(3) * P(4) * P(5)$

$Pr =\frac{1}{35} *\frac{1}{34}*\frac{1}{33}*\frac{1}{32}*\frac{1}{31}$

$Pr =\frac{1}{35*34*33*32*31}$

$Pr =\frac{1}{38955840}$