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Andre45 [30]
3 years ago
6

In a certain lottery, five different numbers between 1 and 35 inclusive are drawn. These are the winning numbers. To win the lot

tery, a person must select the correct 5 numbers in the same order in which they were drawn. What is the probability of winning
Mathematics
1 answer:
Goryan [66]3 years ago
3 0

Answer:

Pr =\frac{1}{38955840}

Step-by-step explanation:

Given

n = 35 ---- 1 to 35

r = 5 -- selection

Required

The probability of winning

The probability of getting the first number correctly is:

P(1) = \frac{1}{35}

At this point, the remaining numbers are 34

So, the second selection has the following probability

P(2) = \frac{1}{34}

Following the above sequence, we have:

P(3) = \frac{1}{33}

P(4) = \frac{1}{32}

P(5) = \frac{1}{31}

So, the required probability is:

Pr =P(1) * P(2) * P(3) * P(4) * P(5)

Pr =\frac{1}{35} *\frac{1}{34}*\frac{1}{33}*\frac{1}{32}*\frac{1}{31}

Pr =\frac{1}{35*34*33*32*31}

Pr =\frac{1}{38955840}

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pochemuha
So you have the equations
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