(x-5)(x+3)=0
x^2+3x-5x-15=0
(x^2+3x) (-5x-15)
x(x+3) -5(x+3)
x-5=0 x+3=0
x=5 OR -3
A. 100/20
The distance in meters should be divided by the time in seconds to get the value of the distance in meters travelled in one second.
Answer:
Shown - See explanation
Step-by-step explanation:
Solution:-
- The given form for rate of change is:
8 sec(x) tan(x) − 8 sin(x).
- The form we need to show:
8 sin(x) tan2(x)
- We will first use reciprocal identities:

- Now take LCM:

- Using pythagorean identity , sin^2(x) + cos^2(x) = 1:

- Again use pythagorean identity tan(x) = sin(x) / cos(x):

0.13 cents per minute
$50 per month
13 goes into 5,000 = 384
384 minutes per month
We know that AXB + CYD and AXB + FZE = 90
20 + CYD = 90 and 20 + FZE = 90
We can see that CYD and FZE are equal so we can use one equation
Let's use 20 + CYD = 90
CYD = 70 and FZE is also equal to 70 because CYD and FZE are equal.
so 70 + 70 = 140 degree