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andriy [413]
3 years ago
15

In a Compton scattering experiment, scattered photon is found to have its wavelength three times of the incident photon for the

scattering angle of 180°. Calculate Wavelengths (in nm) of the incident, scattered photon, and Compton shift.​
Physics
1 answer:
Svetlanka [38]3 years ago
5 0

Answer:

Two of Einstein’s influential ideas introduced in 1905 were the theory of special relativity and the concept of a light quantum, which we now call a photon. Beyond 1905, Einstein went further to suggest that freely propagating electromagnetic waves consisted of photons that are particles of light in the same sense that electrons or other massive particles are particles of matter. A beam of monochromatic light of wavelength \lambda (or equivalently, of frequency f) can be seen either as a classical wave or as a collection of photons that travel in a vacuum with one speed, c (the speed of light), and all carrying the same energy, {E}_{f}=hf. This idea proved useful for explaining the interactions of light with particles of matter.

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almond37 [142]

Answer:

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2 years ago
Physics problem: piston? The piston of a hydraulic automobile lift is 0.300 m in diameter. 1. What gauge pressure, in pascals, i
k0ka [10]
Pressure is given by:
P=F/A
force=1200*10=12000 N
Area=pi*r^2=3.14*0.15^2
=0.07065 m^2
Thus;
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but
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3 0
3 years ago
Read 2 more answers
The volume of a piece of metal of a mass 6 gram is 15cm3. What is the density of the metal piece?
torisob [31]

Answer:

0.4 g/cm^3

Explanation:

The density of an object can be found using the following formula.

d= m/v

where m is the mass and v is the volume.

The mass of the metal is 6 grams and the volume is 15 centimeters^3

m=6 g

v= 15 cm^3

Substitute these into the formula.

d= 6 g/ 15 cm^3

Divide 6 g by 15 cm^3 (6/15=0.4)

d= 0.4 g/ cm^3

The density of the metal is 0.4 grams per cubic centimeter.

4 0
3 years ago
Read 2 more answers
What is the electron configuration of oxygen? 1s22s22p3 1s2, 2s6, 2p4, 3s2 1s2, 2s2, 2p4, 3s2 1s22s22p4
vaieri [72.5K]

oxygen's atomic number is 8

1s22s22p4 is the electron configuration

2+2=4 4+4=8

7 0
3 years ago
Read 2 more answers
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