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Novosadov [1.4K]
3 years ago
15

What is the electron configuration of oxygen? 1s22s22p3 1s2, 2s6, 2p4, 3s2 1s2, 2s2, 2p4, 3s2 1s22s22p4

Physics
2 answers:
Shalnov [3]3 years ago
8 0

Answer:

(D) 1s22s22p4

Explanation: The last option is the correct answer !

vaieri [72.5K]3 years ago
7 0

oxygen's atomic number is 8

1s22s22p4 is the electron configuration

2+2=4 4+4=8

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It is a chemical change because the salt is dissolving.
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Which element has the strongest attraction for electrons
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When the displacement of a mass on a spring in simple harmonic motion is A/2 from the equilibrium position, what fraction of the
KonstantinChe [14]

Answer:

The ratio is  KE : TM  =  0.75

Explanation:

from the question we are told that

  The displacement of a mass on a spring in simple harmonic motion is A/2 from the equilibrium position

Generally the total mechanical  energy of the mass is mathematically represented as

        TM  =  \frac{1}{2}  *  k  *  A^2

Here  k is the spring constant  ,  A is the total displacement of the  the mass  from maximum  compression to maximum extension of the spring

Generally this total mechanical energy is mathematically represented as

        TM  =  KE  + PE

=>     KE = TM  - PE

Here the potential  energy of the mass is mathematically represented as

     PE   = \frac{1}{ 2}  *  k *  [ x ]^2

Here x is the displacement of the mass from maximum compression or extension of the spring to equilibrium position and the value is  

      x = \frac{A}{2}

So

     PE   = \frac{1}{ 2}  *  k *  [ \frac{A}{2}  ]^2

So

      KE =  \frac{1}{2}  *  k  *  A^2 - \frac{1}{2}  *  k  *  [\frac{A}{2} ]^2

=>    KE =  \frac{1}{2}  *  k  *  A^2 - \frac{1}{8}  *  k  *  A ^2

=>    KE =  0.375  *  k  *  A^2

So the ratio of  KE :  TM is  mathematically represented as

       \frac{KE}{TM} =  \frac{0.375  k A^2 }{0.5 k A^2}

=>    \frac{KE}{TM} = 0.75

3 0
2 years ago
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What is the weight of a 4.2 kg bowling ball on Mars?

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Hope this helps

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3 years ago
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