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Novosadov [1.4K]
4 years ago
15

What is the electron configuration of oxygen? 1s22s22p3 1s2, 2s6, 2p4, 3s2 1s2, 2s2, 2p4, 3s2 1s22s22p4

Physics
2 answers:
Shalnov [3]4 years ago
8 0

Answer:

(D) 1s22s22p4

Explanation: The last option is the correct answer !

vaieri [72.5K]4 years ago
7 0

oxygen's atomic number is 8

1s22s22p4 is the electron configuration

2+2=4 4+4=8

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A softball player swings a bat, accelerating it from rest to 2.6 rev/srev/s in a time of 0.20 ss . Approximate the bat as a 0.90
svetoff [14.1K]

Answer:

\tau=22.13Nm

Explanation:

information we have:

mass: m=0.9kg

lenght: L=0.95m

frequency: f=2.6rev/s

time: t=0.2s

and from the information we have we can calculate the angular velocity \omega. which is defined as

\omega=2\pi f

\omega=2\pi (2.6rev/s)\\\omega=16.336 rev/s

----------------------------

Now, to calculate the torque

We use the formula

\tau=I \alpha

where I  is the moment of inertia and \alpha is the angular acceleration

moment of inertia of a uniform rod about the end of it:

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substituting known values:

I=\frac{1}{3} (0.9kg)(0.95m)^2\\I=0.271kg/m^2

for the torque we also need the acceleration \alpha which is defined as:

\alpha=\frac{\omega}{t}

susbtituting known values:

\alpha=\frac{16.336rev/s}{0.2s} \\\alpha=81.68rev/s^2

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5 0
4 years ago
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3 years ago
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3 years ago
A massless spring with force constant ????=200N/m hangs from the ceiling. A 2.0-kg block is attached to the free end of the spri
Makovka662 [10]

Answer:

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P=mgh\\\Rightarrow P=2\times 9.81\times 0.17\\\Rightarrow P=3.3354\ J

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