Find the mean for both:
Sierra: 2 + 11 + 12 + 13 + 15 = 53
53/5 =10.6
Median is the middle value = 12
Alek: 9 + 11 + 11 + 12 + 13 = 56
56/5 = 11.2
Median = 11
A: The medians do not equal the mean.
B: Sierra's are more spread out, ( no identical ages and a greater range ).
C: Sierra's mean is less than Alek.
D. Sierra has an outlier (2).
The answer would be B
Given:
<span>11 11.5 10.5 17 14.5 14.5 18 17 19
Arrange in chronological order from least to greatest.
10.5 ; 11 ; 11.5 ; 14.5 ; 14.5 ; 17 ; 17 ; 18 ; 19
</span><span>I used an online lower and upper fence calculator to get the necessary data.
Minimum: 10.5
Maximum: 19
Q1: 11.25
Q2 or median: 14.5
Q3: 17.5
Interquartile range can be solved by subtracting the value of Q1 from the value of Q3
IQR = Q3 - Q1
IQR = 17.5 - 11.25
IQR = 6.25 CHOICE A. </span>
Answer:
$141.33
Step-by-step explanation:
He gave $100 to one fried and 158.67 to another
100+158.67=258.67
An example would be x = 2 and y = 1:-
√2 + 1 = √2 + √1
because √1 = 1
Answer:
Given that the events A and B are mutually exclusive.
P(A) = 0.1
P(B) = 0.4
Mutually Exclusive Events: When two events are Mutually Exclusive it is impossible for them to happen together i.e
If A and B are two events then; P(A and B) = 0
then;
P(A or B) = P(A) +P(B)
By the definition of mutually exclusive events;
P(A or B) = P(A) +P(B) ......[1]
Substitute the values of P(A) = 0.1 and P(B) = 0.4 in [1] we have;
P(A or B) = P(A) +P(B) = 0.1+0.4 = 0.5
