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saveliy_v [14]
3 years ago
7

The perimeter of a rectangle is 48 centimeters. The relationship between the length, the width, and the perimeter of the rectang

le can be described with the equation: 2 • length + 2 • width = 48. Find the length, in centimeters, if the width is
A.20.4
B. 24.1
C.21.4
D.22.3
Mathematics
1 answer:
vaieri [72.5K]3 years ago
8 0
Probably A I am not really sure I am trying sorry if it is wrong
You might be interested in
.
USPshnik [31]

Answer:

  • $17,500 at 8%
  • $17,500 at 14%

Step-by-step explanation:

The fraction that needs to be invested at the higher rate is ...

  (11% - 8%)/(14% -8%) = 3%/6% = 1/2

Half the money should be invested at each of the rates:

  $17,500 for 8% return

  $17,500 for 14% return.

_____

If you let x represent the amount at the higher rate, then the total return is ...

  14%x + 8%(35000 -x) = 11%(35000)

  (14% -8%)x = (11% -8%)(35000) . . . . subtract 8%·35000

  x = (11% -8%)/(14% -8%)×35000 . . . . divide by the coefficient of x

Note that this formula is exactly the one we started with, above.

4 0
2 years ago
Felipe's Coffee Shop makes a blend that is a mixture of two types of coffee. Type A costs Felipe $4.55 per lb. Type B costs $5.7
RUDIKE [14]

Answer:

Type A coffee in lbs = 97 lbs

Step-by-step explanation:

Type a = 4.55/lbs = x

type b = 5.70/lbs =  y

Total in lbs = 147lbs

total in sales = 726.50

First,

x + y = 147 lbs    -------------------equ 1

4.55x + 5.70y = lbs    ------------ equ 2

<em>Multiply equ 1 by 4.55</em>

4.55x + 4.55y = 668.85  -------------equ 3

4.55x + 5.70y = 726.50   ------------equ 4

<em>Subtracting equ 3 from equ 4</em>

1.15y = 57.65

y = 50

<em>Substituting y = 50 into equ 1</em>

x + 50 = 147

x = 97

7 0
3 years ago
Evaluate 4 + 6 x 6 / 8
dybincka [34]

Answer:

8.5

Step-by-step explanation:

4 + (6)(6)/8=

17/2 = 8.5

5 0
1 year ago
Read 2 more answers
Find the area of the trapezoid.
kakasveta [241]
I think the answer is 47.6 also
6 0
3 years ago
Y as a function of x<br><br> Is this a function. Show your work
lord [1]
Plot the graph then you do the vertical line test. You draw a vertical line on the graph. If the line touches the graph at just one point,note just one point then it is a function
8 0
3 years ago
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