1.
An expression of the form

is called a "compound fraction"
Compound fractions can be written as simple fractions by multiplying c to a, and then adding the product to c as follows:

for example,

can be written as:

2.
when we subtract or add a fraction

from an integer k,
we first write k as a fraction with denominator n. We can do this as follows:

for example, if we want to subtract

from 8,
we first write 8 as a fraction with denominator 2:

3.
Thus,

4.
The simple fraction 7/2 is not an option, so we write it as a compound fraction as follows:

(So write 7 as the sum of the largest multiple of 2, smaller than 7 + what is left. In our case these numbers are 6 and 1, then proceed as shown)
5. Answer: D
Answer:
a. k = n - 1 b. 15 c. 112
Step-by-step explanation:
I can answer a. b. and c. for you!
For a. let's say that the variable k means keys. And n means bits.
Since Millie can collect one less keys than there are bits, the equation is....
*See top*
For b. if Antonio has a 16-bit system, by looking at our equation we know that k = n - 1.
So, if n = 16, k = 15
For c. if each byte equals 8 bits, and there are 14 bytes, then the amount of bits would be 8 x 14.
8 x 14 = 112
Answer:
2 to the 20th power over 3 to the 12th power
Step-by-step explanation:
Numerator: base = 2. Power=5*4=20
Denominator :base 3 Power=3*4=12
Answer:
Question Number 2 is 20
Question number 3 is 18x-32
Step-by-step explanation: