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3 years ago

15

What is the value of the digit 8 in the number 14.812?

2 answers:

schepotkina [342]3 years ago

8 0

The 8 is in the Tenth place value

o-na [289]3 years ago

7 0

Answer:

the tenth or 0.1

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What step do I do next ?

Svetach [21]

When it comes to dividing decimals, bear in mind that, first off you'd want to do away with the decimal point.

now, "you add as many zeros to the other term, as it has decimals", what the heck does that mean?

for example 2.135 ÷ 5

notice, the 2.135 has three decimals, namely three numbers to the right of the decimal point.

since 2.135 has three decimals, then what we do, we add three zeros to 5, AND do away with the decimal point, thus our division is really

2135 ÷ 5000, which is 0.427

now, if we had 2.135 ÷ 5.79

what we do is, since 2.135 has three decimals, we add three zeros to 5.79, and since 5.79 has two decimals, we add two zeros to 2.135, then our division is really

213500 ÷ 579000 <-- notice, no dot on both

which is about 0.3687392

anyhow, that said, check the picture below

5 0

3 years ago

Please help me quickly

Scilla [17]

Divide 4 to both sides of the equation

8 0

3 years ago

Read 2 more answers

The depth of water in a swimming pool decreases by 1/8 inch per day due to evaporation. No water is added to the pool for a 2-we

Blababa [14]

Answer:

uwiejejdkdm

Step-by-step explanation:

द्ज्द्क्क्स्क्द्क्क्द्क्द्क्द्क्फोक्स्म्स्वेज्र

3 0

2 years ago

Eliminate the parameter and obtain the standard form of the rectangular equation. line through (x1, y1) and (x2, y2): x = x1 + t

Helen [10]

The parametric equations for the line passes through the points (X₁ , Y₁) and (X₂ , Y₂) are :

X = X₁ + t (X₂ - X₁) ......................... (1)

Y = Y₁ + t (Y₂ - Y₁) .......................... (2)

For eliminating the parameter (t) , first we will solve any one equation for 't' and then substitute that into another equation.

From the equation (1),

⇒ t = $\frac{X- X1}{(X2 - X1)}$

Substituting this t = $\frac{X- X1}{(X2 - X1)}$ into the equation (2), we will get :

Y = Y₁ + $\frac{(X- X1)}{(X2 - X1)}$ (Y₂ - Y₁)

Y = Y₁ + $\frac{(X- X1)(Y2 - Y1)}{(X2 - X1)}$

So, this is the standard form of rectangular equation.

For two given points (0, 0) and (4, -4)

X₁ = 0 , Y₁ = 0, X₂ = 4 and Y₂ = -4

For finding the parametric equations, we will plug these values into the given parametric equations.

X = X₁ + t (X₂ - X₁)

⇒ X = 0+ t (4 - 0)

⇒ X = 4t

and Y = Y₁ + t (Y₂ - Y₁)

⇒ Y = 0+ t (-4 - 0)

⇒ Y = - 4t

So, the parametric equations for the line passing through (0,0) and (4, -4) are: X = 4t and Y = -4t

6 0

3 years ago

Aswer the whole page for 28 points

Artist 52 [7]

The picture is extremely blurry, could you write out some of the answers?

6 0

2 years ago