3 and what?
if it is 3 and 5 than the answer would be 15
This should help you here are the steps of your problem :)
2*(1/2)*r+2*r+1 = 9*(1/10) // - 9*(1/10)
2*(1/2)*r+2*r-(9*(1/10))+1 = 0
2*(1/2)*r+2*r-9/10+1 = 0
3*r+1/10 = 0 // - 1/10
3*r = -1/10 // : 3
r = -1/10/3
r = -1/30
r = -1/30
So your answer would be 1/30
By elimination:
y = 3x - 1
y = 2x + 2
Subtract the second equation from the first
0 = x - 1
y = 2x + 2
Subtract the first equation from the second
0 = x - 1
y = x + 3
Subtract the first equation from the second again
0 = x - 1
y = 4
Subtract x from both sides of the first equation
- x = - 1
y = 4
Divide the first equation by (-1)
x = 1
y = 4
<h3>
So, the solution is x = 1 and y = 4 {or: (1, 4)}</h3>
Answer:The distance from a point to a line is
distance(ax+by+c=0,(x0,y0)) = abs(ax0+by0+c)/sqrt(a^2+b^2)
So first convert the formula for the line to standard form
5x+2y=4
5x+2y-4=0
a=5, b=2, c=-4, x0=15, y0=-21
Step-by-step explanation:
