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jeka57 [31]
3 years ago
9

The grade six pupils decided to have an income generating project. They make

Mathematics
1 answer:
lara31 [8.8K]3 years ago
8 0

Answer:

c. P 2.40

Step-by-step explanation:

P 100 spent, 50 pieces made. Therefore P2 a piece. 20% of P2 is .40. Therefore total is 2 + .40 = P2.40

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*I'll be keeping the solutions in exact form*

So firstly, square root both sides. This will split the equation into two:

3x-1=\sqrt{5} \\ 3x-1=-\sqrt{5}

Next, add 1 on each side: 3x=\sqrt{5}+1 \\ 3x=-\sqrt{5}+1

Next, divide 3 on both sides, and your answers will be x=\frac{\sqrt{5}+1}{3},\frac{-\sqrt{5}+1}{3}

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Answer:4=1000000000 to the 9th power 376= 7292038183038293948 centimeters

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sin (t) > 0  and cos (t) < 0  only in Quadrant II


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A school group is helping plant a new city garden. Today they used 12 1/2 pounds of potting soil and planted 2/5 of the garden.
Len [333]

Answer:

18\frac{3}{4} pounds.  

Step-by-step explanation:

Let x be the total amount of potting soil needed to complete the planting in new garden.    

We are told that a school group is helping plant a new city garden. Today they used 12 1/2 pounds of potting soil and planted 2/5 of the garden. This means 2/5 of x equals to 12 1/2.

\frac{2}{5} x=12\frac{1}{2}

\frac{2}{5} x=\frac{25}{2}  

x=\frac{25}{2}\times\frac{5}{2}

x=\frac{125}{4}

To find the amount of soil needed for the next of planting we will subtract the amount of potting soil used on the first day (\frac{25}{2}) from amount of total potting soil (\frac{125}{4}).

\text{Amount of potting soil needed for second day}=\frac{125}{4}-\frac{25}{2}

\text{Amount of potting soil needed for second day}=\frac{125}{4}-\frac{25\times 2}{2\times2}

\text{Amount of potting soil needed for second day}=\frac{125}{4}-\frac{50}{4}

\text{Amount of potting soil needed for second day}=\frac{75}{4}

\text{Amount of potting soil needed for second day}=\frac{75}{4}=18\frac{3}{4}

Therefore, the group will need 18\frac{3}{4} pounds of potting soil to finish their work.            

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