Answer:
Since the calculated value of t =-0.427 does not fall in the critical region so we accept H0 and conclude that there is enough evidence to show that mean difference in the age of onset of symptoms and age of diagnosis is 25 months .
Step-by-step explanation:
The given data is
Difference d= -24 -12 -55 -15 -30 -60 -14 -21 -48 -12 -25 -53 -61 -69 -80
∑ d= -579
∑d²= 29871
1) Let the hypotheses be
H0: ud= 25 against the claim Ha: ud ≠25
H0 : mean difference in the age of onset of symptoms and age of diagnosis is 25 months .
Ha: mean difference in the age of onset of symptoms and age of diagnosis is not 25 months.
2) The degrees of freedom = n-1= 15-1= 14
3) The significance level is 0.05
4) The test statistic is
t= d`/sd/√n
The critical region is ║t║≤ t (0.025,14) = ±2.145
d`= ∑di/n= -579/15= -38.6
Sd= 23.178 (using calculators)
Therefore
t= d`/ sd/√n
t= -38.6/ 23.178√15
t= -1.655/3.872= -0.427
5) Since the calculated value of t =-0.427 does not fall in the critical region so we accept H0 and conclude that there is enough evidence to show that mean difference in the age of onset of symptoms and age of diagnosis is 25 months .
Answer:
{PP, PR, RP, RR}
Step-by-step explanation:
Given that:
Passenger vehicle = P
Recreational vehicle = R
For each of the next two vehicles :
Sample space :
_____ P ______ R
P ___ PP _____ PR
R ___ RP _____ RR
{PP, PR, RP, RR}
B.) Tree diagram can be found in attached picture
Answer:
19th term = ar^18
19th term = 774,840,978
Step-by-step explanation:
First term, a = 2
Common ratio, r = 3
nth term of a geometric sequence = ar^(n-1)
19th term = ar^(19-1)
19th term = ar^18
= 2 × 3^18
= 2 × 387,420,489
= 774,840,978
19th term = 774,840,978
Answer is D. for every 1 small mouth caught, it is estimated you will catch 3 largemouth bass
