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PtichkaEL [24]
3 years ago
10

Multiplying polynomials find the product (2a-1)(8a-5)

Mathematics
2 answers:
Readme [11.4K]3 years ago
5 0
(2a - 1) (8a - 5)

= {2a(8a - 5)} - {1(8a - 5)}

= 16a² - 10a - 8a + 5

= 16a² - 18a + 5
Yuki888 [10]3 years ago
4 0
(2a-1)(8a-5)=2a\cdot 8a-2a\cdot 5-8a\cdot 1-5\cdot (-1)=\\ \\=16a^2-10a-8a+5=16a^2-18a +5


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Lelu [443]

let's calculate it step by step.

I'll assume that the function we look for is quadratic, because we only got 3 points

I plotted the 3 points for checking the equation later, and some intuited insight. see screenshot 1

let's write the general form of quadratic equations:

f(x) = a*x² + b*x + c

our goal is to correctly determine a, b and c

since we know from the 2nd point that

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we can say

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this one comes almost for free

now to the next point, the 3rd one

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we can write it as

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we can rearrange that to

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we just swapped a for what its equal to.

now we just got numbers and b's

simplify it to

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a = -(-29/6) -7

a = 29/6 -42/6

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now that we got a, b and c we can write the whole equation

<em><u>f(x) = -13/6*x² -29/6*x +4</u></em>

see the graphic check in screenshot 2

second part of the problem:

if we want to move the whole graph 4 units down, we effectivly just cancel the +4 part

g(x) = f(x) -4 = f(x) = -13/6*x² -29/6*x +4 -4

<em><u>g(x) = -13/6*x² -29/6*x</u></em>

see screenshot 3 for the graph

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Answer:

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