3 years ago

Multiplying polynomials find the product (2a-1)(8a-5)

2 answers:

5 0

(2a - 1) (8a - 5)

= {2a(8a - 5)} - {1(8a - 5)}

= 16a² - 10a - 8a + 5

= 16a² - 18a + 5

4 0

$(2a-1)(8a-5)=2a\cdot 8a-2a\cdot 5-8a\cdot 1-5\cdot (-1)=\\ \\=16a^2-10a-8a+5=16a^2-18a +5$

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