Below are suppose the be the questions:
a. factor the equation
<span>b. graph the parabola </span>
<span>c. identify the vertex minimum or maximum of the parabola </span>
<span>d. solve the equation using the quadratic formula
</span>
below are the answers:
Vertex form is most helpful for all of these tasks.
<span>Let </span>
<span>.. f(x) = a(x -h) +k ... the function written in vertex form. </span>
<span>a) Factor: </span>
<span>.. (x -h +√(-k/a)) * (x -h -√(-k/a)) </span>
<span>b) Graph: </span>
<span>.. It is a graph of y=x^2 with the vertex translated to (h, k) and vertically stretched by a factor of "a". </span>
<span>c) Vertex and Extreme: </span>
<span>.. The vertex is (h, k). It is a maximum if "a" is negative; a minimum otherwise. </span>
<span>d) Solutions: </span>
<span>.. The quadratic formula is based on the notion of completing the square. In vertex form, the square is already completed, so the roots are </span>
<span>.. x = h ± √(-k/a)</span>
By making a line plot you first make a frequency table then you make the line plot
but with fractions u dont make a frequency table you just ordedr the fractions least to greatest i think
Answer:
I have provided it below
Step-by-step explanation:
- 8/18 > - 17/27
- 0.444444 > 0.62963
So this inequality is TRUE
Hope this helps!!
Answer:
Circumscribed circle: Around 80.95
Inscribed circle: Around 3.298
Step-by-step explanation:
Since C is a right angle, when the circle is circumscribed it will be an inscribed angle with a corresponding arc length of 2*90=180 degrees. This means that AB is the diameter of the circle. Since the cosine of an angle in a right triangle is equivalent to the length of the adjacent side divided by the length of the hypotenuse:
To find the area of the circumscribed circle:
To find the area of the inscribed circle, you need the length of AC, which you can find with the Pythagorean Theorem:
The area of the triangle is:
The semiperimeter of the triangle is:
The radius of the circle is therefore 
The area of the inscribed circle then is 
.
Hope this helps!
