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lakkis [162]
3 years ago
15

In a quadrilateral ABCD, AO and BO are bisectors of angle A and angle B respectively

Mathematics
1 answer:
worty [1.4K]3 years ago
3 0

Answer: ABCD is a quadrilateral

To prove : ∠AOB=

2

1

​

(∠C+∠D)

AO and BO is bisector of A and B

∠1=∠2∠3=∠4...(1)

∠A+∠B+∠C+∠D=360

(Angle sum property)

2

1

​

(∠A+∠B+∠C+∠D)=180...(2)

In △AOB

∠1+∠3+∠5=

2

1

​

(∠A+∠B+∠C+∠D)

∠1+∠3+∠5=∠1+∠3+

2

1

​

(∠C+∠D)

∠AOB=

2

1

​

(∠C+∠D)

​

Explanation: In a quadrilateral ABCD. AO and BO are bisectors of angle A and angle B respectively. Prove that ∠AOB=

2

1

​

{∠C+∠D}.

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Galina-37 [17]
392,000 would be the nearest <span>hundred thousand</span>
6 0
3 years ago
the vertex of this parabola is at (2,-1). when the y-value is 0, the x-value is 5. what is the coefficient of the squared term i
timama [110]
We know that

case a)
the equation of the vertical parabola write in vertex form is
y=a(x-h)²+k,
where (h, k) is the vertex.

Using our vertex, we have:
y=a(x-2)²-1
We know that the parabola goes through (5, 0),

so
we can use these coordinates to find the value of a:
0=a(5-2)²-1
0=a(3)²-1
0=9a-1

Add 1 to both sides:
0+1=9a-1+1
1=9a
Divide both sides by 9:
1/9 = 9a/9
1/9 = a
y=(1/9)(x-2)²-1

the answer is
a=1/9


case b)
the equation of the horizontal parabola write in vertex form is
x=a(y-k)²+h, 
where (h, k) is the vertex.

Using our vertex, we have:
x=a(y+1)²+2, 
We know that the parabola goes through (5, 0),

so
we can use these coordinates to find the value of a:
5=a(0+1)²+2
5=a+2
a=5-2
a=3
x=3(y+1)²+2

the answer is
a=3

see the attached figure 

3 0
3 years ago
How much of a radioactive kind of thorium will be left after 14,680 years if you start with
babymother [125]

Answer:

8978 grams

Step-by-step explanation:

The equation to find the half-life is:

N(t)= N_{0}e^{-kt}

N(t) = amount after the time <em>t</em>

N_{0} = initial amount of substance

t = time

It is known that after a half-life there will be twice less of a substance than what it intially was. So, we can get a simplified equation that looks like this, in terms of half-lives.

N(t)= N_{0}e^{-\frac{ln(\frac{1}{2}) }{t_{h} } t} or more simply N(t)= N_{0}(\frac{1}{2})^{\frac{1}{t_{h} } }

t_{h} = time of the half-life

We know that N_{0} = 35,912, t = 14,680, and t_{h}=7,340

Plug these into the equation:

N(t) = 35912(\frac{1}{2})^{\frac{14680}{7340} }

Using a calculator we get:

N(t) = 8978

Therefore, after 14,680 years 8,978 grams of thorium will be left.

Hope this helps!! Ask questions if you need!!

8 0
2 years ago
The radius of an orange is 1.5 inches.
diamong [38]

Answer:

14.14

Step-by-step explanation:

V=4

3πr3=4

3·π·1.53≈14.13717

5 0
4 years ago
Name two pairs of supplementary angles in the diagram.
Ipatiy [6.2K]

Answer:

Step-by-step explanation:

α + β = 180°

∠BFE and ∠FBC

∠CEF and ∠BCE

6 0
3 years ago
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