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ohaa [14]
3 years ago
15

A picture was marked at $90.00. It was sold at 3/4 of its marked price. What was the sale price?

Mathematics
2 answers:
BaLLatris [955]3 years ago
6 0
The answer is: $22.50
Arte-miy333 [17]3 years ago
4 0

Answer: $67.50

Step-by-step explanation:

Marked price = $90

It is sold at 3/4 of marked price

3/4 of 90

3*4 x 90 = 135/2

= 67.50 = sale price

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ad-work [718]
In addition to mean and sample size you will need the individual scores.

The formula for standard deviation is:

S^2 = E(X-M)^2/N-1

Here's an example: 
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Mean: 3
Sample size: 4

First, put the individual scores one after the other and subtract the mean from it.
4 - 3 = 1
4 - 3 = 1
3 - 3 = 0
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Second, square the answers you got from step 1. 
1^2 = 1
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3 years ago
Joe has eaten 2/5 of a pizza. James has eaten 1/7. How many times more pizza has Joe eaten than James?
11Alexandr11 [23.1K]
First let's make the denominators of the fractions equal.
To do this, we have to find a number which both 5 and 7 divide into.
The smallest number that does this is 35.

2  --> Multiply the numerator by 7
--   
5  --> Multiply the denominator by 7 to get 35

= 14/35

1 --> Multiply the numerator by 5
--
7 --> Multiply the denominator by 5 to get 35

= 5/35

Joe has eaten 14/35 and James has eaten 5/35.
14 / 5 = 2.8

<u>Joe has eaten 2.8 (or 2 4/5) times more pizza than James.</u>




8 0
3 years ago
The radius of a cylinder is 7 c m and its height is 10 c m. Find curved surface area and volume.​
erma4kov [3.2K]

Answer:

  • CSA of the cylinder = 440 sq. cm

  • Volume of the cylinder = 1540 cu. cm

\\

Step-by-step explanation:

Given:

  • Radius of the cylinder = 7 cm
  • Height of the cylinder = 10 cm

\\

To Find:

  • Curved surface area
  • Volume

\\

Solution:

\\

Using formula:

\dashrightarrow \:  \:  { \underline{ \boxed{ \pmb{ \sf{ \purple{CSA  \: of  \: cylinder = 2\pi rh}}}}}}  \:  \star \\  \\

<em>Substituting the required values: </em>

\\

\dashrightarrow \:  \:  \sf CSA {(cylinder)} = 2 \times \dfrac{22}{7} \times 7 \times  10 \\  \\  \\  \dashrightarrow \:  \:  \sf CSA {(cylinder)}  = 2 \times 22 \times 10 \\  \\ \\   \dashrightarrow \:  \:  \sf CSA {(cylinder)} = 44 \times 10 \\  \\  \\  \dashrightarrow \:  \:  \sf CSA {(cylinder)}  = 440 \:  {cm}^{2}  \\ \\ \\

Now,

\dashrightarrow \:  \:  { \underline{ \boxed{ \pmb{ \sf{ \purple{Volume {(cylinder)}=  \pi {r}^{2} h}}}}}}  \:  \star \\  \\ \\

<em>Substituting the required values, </em>

\\

\dashrightarrow \:  \:   \sf Volume {(cylinder)}=  \dfrac{22}{7}  \times  {(7)}^{2}  \times 10 \\ \\  \\  \dashrightarrow \:  \:   \sf Volume {(cylinder)}=  \frac{22}{7}  \times 49  \times 10 \\ \\ \\  \dashrightarrow \:  \:   \sf Volume {(cylinder)}= 22 \times 7 \times 10 \\ \\  \\  \dashrightarrow \:  \:   \sf Volume {(cylinder)}= 1540 {cm}^{3}  \\ \\ \\

Hence,

  • CSA of the cylinder = 440 sq. cm

  • Volume of the cylinder = 1540 cu. cm
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Hello!

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