All categories

3 years ago

Helllllpppp meeeee I neeedddd hellllpppp nowwww pleaseeee

Mathematics

1 answer:

Crank3 years ago

8 0

Answer:

Step-by-step explanation:

They are all integers so they are rational numbers, they are whole numbers as well except there are negative numbers so they are not all natural.

You might be interested in

Prove that ✓-36 does not exist in the Real<br> Numbers

eimsori [14]

Answer:

undefined

Step-by-step explanation:

Becouse any number under a root sign that is negative does not give any answer.Therefore it doesn't exist in real number system.

7 0

3 years ago

(cot theta + cosec theta)/(cosec theta (1 + (cot theta/ cosec theta)).

Margarita [4]

The given expression $\dfrac{\frac{cos \theta}{sin \theta} + \frac{1}{sin\theta} }{\frac{1}{sin \theta} (1+cos \theta)} =1$ is true

<h3>Proving trigonometry identity</h3>

Given the expression

$\frac{cot \theta + cosec \theta}{cosec \theta(1+\frac{cot \theta}{cosec \theta} )} =1$

Note that:

cotθ = cosθ/sinθ
cosecθ = 1/sinθ

Substituting the given parameters into the formula;

$\frac{\frac{cos \theta}{sin \theta} + \frac{1}{sin\theta} }{\frac{1}{sin \theta} (1+cos \theta)} =1$

Find the LCM of both the numerator and denominator

$= \dfrac{\frac{cos \theta + 1}{sin \theta} }{(\frac{1+cos \theta}{sin \theta} )}\\$

Divide the result to have:

$= \frac{1+cos \theta}{sin \theta} \times \frac{sin \theta}{1+cos \theta}\\ = \frac{1}{1}\\ = 1 (Proved)$

Learn more on proofs of trigonometry identity here: brainly.com/question/7331447

4 0

3 years ago

Read 2 more answers

A shipment of 20 similar laptop computers to a retail outlet contains 3 that are defective. If a school makes a random purchase

Sholpan [36]

Answer:

P(X=0) = 0.7158

P(X=1) = 0.2684

P(X=2) =0.0158

Step-by-step explanation:

Number of defective laptops = 3

Number of normal laptops = 17

If the school chooses 2 laptops from this lot, the number of defectives (X) could be 0, 1, or 2.

For zero defectives:

$P(X=0) = \frac{17}{20} *\frac{16}{19}\\P(X=0) = 0.7158$

For one defective:

$P(X=1) = \frac{17}{20} *\frac{3}{19}+\frac{3}{20} *\frac{17}{19}\\P(X=1) = 0.2684$

For two defectives:

$P(X=2) = \frac{3}{20} *\frac{2}{19}\\P(X=2) = 0.0158$

8 0

4 years ago

What is 3.245 rounded to the nearest thousandth

kramer

3.25 is rounded to the nearest thousandth

8 0

4 years ago

Read 2 more answers

The sum of three consecutive even numbers is 90

AleksAgata [21]

Find the cube root of 90 if there isn't, try to compare irrational numbers

8 0

3 years ago