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3 years ago

Figure B is a scale image of Figure A, as shown. What is the scale factor applied to

Mathematics

1 answer:

CaHeK987 [17]3 years ago

4 0

Figure B is 2.8 times larger than figure A. Figure A was multiplied by 2.8 to make figure B

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While watching a circus show, I counted out the number of acrobats and elephants. I counted 40 legs and 15 heads. How many acrob

Goryan [66]

Answer:

y=10 ( number of acrobat)

Step-by-step explanation:

let x be the elephant and y the acrobat

elephant has 4 legs and acrobat 2

4x+2y=40

x+y=15 ⇒x=15-y

substitute for x in the equation:

4(15-y)+2y=40

60-4y+2y=40

-2y=40-60

y=-20/-2

y=10 ( number of acrobat)

number of elephant=15-10=5 elephants

5 0

3 years ago

Write a real-world problem that gives extra information. Tell what the extra information is.

yawa3891 [41]

1.That there is still slavery in the word. CNN 10 reporters caught on film a slave trade in Africa

2. Extra information is adding more information in your sentence to make it seem more interesting

6 0

3 years ago

A dressmaker needs to cut 12-inch pieces of ribbon from rolls of ribbon that are 9 feet in length. How many 12-inch pieces can t

Tems11 [23]

Answer:

so the question is very interesting and the answer is 12 × 15 so the answer is 180 rolls of ribbons

8 0

3 years ago

Sally is planning the school picnic and needs to decide what food vendor to use. She asks 250 students whether they would rather

Oksana_A [137]

Answer:

0.18

Step-by-step explanation:

The relative frequency of eight graders who want fruit smoothie :

Number of eight graders who want fruit smoothie / total number of students surveyed

= 45 / 250

= 0.18

6 0

2 years ago

Show the work please

Kay [80]

Answer:

1) (x + 3)(3x + 2)

2) x= +/-root6 - 1 by 5

Step-by-step explanation:

3x^2 + 11x + 6 = 0 (mid-term break)

using mid-term break

3x^2 + 9x + 2x + 6 = 0

factor out 3x from first pair and +2 from the second pair

3x(x + 3) + 2(x + 3)

factor out x+3

(x + 3)(3x + 2)

5x^2 + 2x = 1 (completing squares)

rearrange the equation

5x^2 + 2x - 1 = 0

divide both sides by 5 to cancel out the 5 of first term

5x^2/5 + 2x/5 - 1/5 = 0/5

x^2 + 2x/5 - 1/5 = 0

rearranging the equation to gain a+b=c form

x^2 + 2x/5 = 1/5

adding (1/5)^2 on both sides

x^2 + 2x/5 + (1/5)^2 = 1/5 + (1/5)^2

(x + 1/5)^2 = 1/5 + 1/25

(x + 1/5)^2 = 5 + 1 by 25

(x + 1/5)^2 = 6/25

taking square root on both sides

root(x + 1/5)^2 = +/- root(6/25)

x + 1/5 = +/- root6 /5

shifting 1/5 on the other side

x = +/- root6 /5 - 1/5

x = +/- root6 - 1 by 5

x = + root6 - 1 by 5 or x= - root6 - 1 by 5

4 0

3 years ago