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3 years ago

Find all the zeros of the equation. -x^3-x^2=11x+11

Mathematics

1 answer:

anyanavicka [17]3 years ago

7 0

Answer:

x= -1 , i(sqrt11) , -i(sqrt11)

Step-by-step explanation:

subtract 11x from both sides

-x^3 - x^2 - 11x = 11

subtract 11 from both sides

-x^3 - x^2 - 11x - 11 = 0

Factor the left side of the equation

- (x - 1)(x^2 + 11) = 0

Set both factors to zero and solve for x

x + 1 = 0 x^2 + 11 = 0

-1 -11

x^2 = -11

x = -1 x = +/- i(sqrt11)

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4 years ago

Someone please help Austin writes down a random number. What is the probability that the number he wrote down is an odd number A

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3 years ago

A culture started with 5000 bacteria after three hours it grew 6500 bacteria predict how many bacteria will be present after 13

charle [14.2K]

Answer:

15595 bacteria will be present after 13 hours.

Step-by-step explanation:

Continuous population growth:

The continuous population growth model, for the population after t hours, is given by:

$P(t) = P(0)e^{rt}$

In which P(0) is the initial population and r is the growth rate.

Started with 5000 bacteria

This means that $P(0) = 5000$

$P(t) = 5000e^{rt}$

After three hours it grew 6500 bacteria:

This means that $P(3) = 6500$ . We use this to find r.

$P(t) = 5000e^{rt}$

$6500 = 5000e^{3r}$

$e^{3r} = \frac{65}{50}$

$\ln{e^{3r}} = \ln{\frac{65}{50}}$

$3r = \ln{\frac{65}{50}}$

$r = \frac{\ln{\frac{65}{50}}}{3}$

$r = 0.0875$

$P(t) = 5000e^{0.0875t}$

How many bacteria will be present after 13 hours?

This is P(13). So

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Rounding to the nearest whole number

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3 years ago

The average birth weight of elephants is 200 pounds. Assume that the distribution of birth weights is Normal with a standard dev

zhenek [66]

The birth weight of elephants at the 85th percentile is 262.16 pounds

<h3>What is the standard deviation?</h3>

Standard deviation is defined as the amount of variation or the deviation of the numbers from each other.

Given that:-

The average birth weight of elephants is 200 pounds $\mu$ = 200

The deviation of 60 pounds. $\sigma$ = 60

The birth weight of elephants at the 85th percentile. z = 85%= 1.036

Now from the formula of z-score:-

$z=\dfrac{x-\mu}{\sigma}\\\\\\z=\dfrac{x-200}{60}\\\\\\1.036\times 60=x-200\\\\\\x=\ \ 262.16\ pounds$

Hence the birth weight of elephants at the 85th percentile is 262.16 pounds

To know more about standard deviation follow

brainly.com/question/475676

#SPJ1

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2 years ago