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stepladder [879]
3 years ago
13

Wavelength and Frequency

Mathematics
1 answer:
sp2606 [1]3 years ago
7 0

Answer:

B. 3 to 2

Step-by-step explanation:

I calculated it logically

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Convert
REY [17]
The answer would be A) .1875
5 0
3 years ago
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the present age of prisca and Ashmaal are in ratio 2:3 . After 4 yrs the ratio of their ages will be 4:5 the present age of pris
Solnce55 [7]

Answer:

he Present age of Prisca will be 4 years  .

Step-by-step explanation:

Given as :

The ratio of present age of Prisca and Ashmaal = 2 : 3

Let The present age of Prisca = 2 x  years

Let The present age of Ashmaal = 3 x  years

After 4 years , the ratio of present age = 4 : 5

i.e \frac{ 2 x + 4}{3 x + 4} = \frac{4}{5}

Or,  5 × (2 x + 4) = 4 × (3 x + 4)

Or, 10 x + 20 = 12 x + 16

Or, 12 x - 10 x = 20 - 16

Or, 2 x = 4

∴  x = \frac{4}{2}

i.e x = 2

So, The present age of Prisca = 2 x = 2 × 2 = 4 years

And The present age of Ashmaal = 3 x = 3 × 2 = 6 years

Hence, The Present age of Prisca will be 4 years  . Answer

4 0
4 years ago
Solve the following equation. Show your work.<br><br> 2(x-4) = 5(x+1)
baherus [9]
2x-8=5x+5
5x-2x=-8-5
3x=-13
x=-13/3,
or 
x=-4 1/3
4 0
4 years ago
The distance between new York city and los angeles is 4090 kilometers. What is the distance in miles?
spin [16.1K]

Hi!

1 mile = 1.6 km

x miles = 4090 km

________________

x = (4090*1)/1,5

x = 2556,25 miles

Hope this helps!

3 0
4 years ago
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Which matrix is the product of a 3 × 3 identity matrix and the scalar 3?
Ludmilka [50]

Answer:

\left[\begin{array}{ccc}3&0&0\\0&3&0\\0&0&3\end{array}\right]

Step-by-step explanation:

In order to find out the resulting matrix, we will have to multiply the identity matric and the scalar 3:

The 3x3 identity matrix is:

\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right]

Multiplying with scalar 3:

3\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right]

The scalar will be multiplied by each element of the matrix.

Multiplying zeros with scalar 3 will give us zero. So the resulting matrix will be:

\left[\begin{array}{ccc}3*1&0&0\\0&3*1&0\\0&0&3*1\end{array}\right] = \left[\begin{array}{ccc}3&0&0\\0&3&0\\0&0&3\end{array}\right]

So the resultant matrix will be a scalar matrix with 3 at diagonal positions..

5 0
3 years ago
Read 2 more answers
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