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Rudik [331]
3 years ago
14

SOMEONE PLEASE GIVE STEP BY STEP ILL GIVE BRAINLIEST

Mathematics
1 answer:
Natalija [7]3 years ago
8 0

Answer:

18.9 or 23.625

Step-by-step explanation:

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PLEASE HELPPPP!!!!!!!!!!
Elza [17]

Answer:

8x15x12=1440

Step-by-step explanation:

7 0
3 years ago
The expression (8-3)^2-(5-2)^2 is equivalent to what numerical expression
Tresset [83]
(8-3)²-(5-2)²
Follow the PEMDAS
P-Parenthesis
E-Exponents
M/D-Multiplication/Division
A/S-Addition/Subtraction
clear the numerals in the parenthesis:
(5)²-(3)²
Now do the exponents:
=25-9
=16
Its just: (5)²-(3)²
7 0
3 years ago
Reflect shape A in the line y = x.
marshall27 [118]

Answer:

I didn't know and I tried ‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️

8 0
2 years ago
2 points
Stels [109]

Answer:

C

Step-by-step explanation:

You have to multiply

3 0
3 years ago
Three populations have proportions 0.1, 0.3, and 0.5. We select random samples of the size n from these populations. Only two of
IRINA_888 [86]

Answer:

(1) A Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

Step-by-step explanation:

Consider a random variable <em>X</em> following a Binomial distribution with parameters <em>n </em>and <em>p</em>.

If the sample selected is too large and the probability of success is close to 0.50 a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

  • np ≥ 10
  • n(1 - p) ≥ 10

The three populations has the following proportions:

p₁ = 0.10

p₂ = 0.30

p₃ = 0.50

(1)

Check the Normal approximation conditions for population 1, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.10=1

Thus, a Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2)

Check the Normal approximation conditions for population 2, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.30=310\\\\n_{c}p_{1}=50\times 0.30=15>10\\\\n_{d}p_{1}=40\times 0.10=12>10\\\\n_{e}p_{1}=20\times 0.10=6

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3)

Check the Normal approximation conditions for population 3, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.50=510\\\\n_{c}p_{1}=50\times 0.50=25>10\\\\n_{d}p_{1}=40\times 0.50=20>10\\\\n_{e}p_{1}=20\times 0.10=10=10

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

8 0
3 years ago
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