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madam [21]
3 years ago
10

A librarian knows that 45% of the books currently checked out will NOT be returned on the due date. The library has a

Mathematics
1 answer:
malfutka [58]3 years ago
7 0

Answer:

79 books

Step-by-step explanation:

45% books not returned = 55% books will be returned

145 books currently checked out

55% of 145 = 79.75

since you can't return 3/4 of a book, i would round down to 79.

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Classify the following into monomials, binomial and trinomials.
Degger [83]
  • A monomial is an expression containing a single term.
  • A binomial is an expression having two terms.
  • A trinomial is an expression having three terms.

  1. Here -6 is a monomial having a single term -6.
  2. -5 + x is a binomial containing two terms -5 and x.
  3. 32x - y is a binomial having two terms 32x and -y.
  4. 6x² + 5x - 3 is a trinomial having three terms 6x², 5x and -3.
  5. z² +2 is a binomial having two terms z² and 2.

<u>Answers</u>

  1. <u>monomial</u>
  2. <u>binomial</u>
  3. <u>binomial</u>
  4. <u>trinomial</u>
  5. <u>binomial</u>

Hope you could understand.

If you have any query, feel free to ask.

5 0
2 years ago
A recipe calls for an oven to be preheated to 400 °F. What is the approximate temperature of the preheated oven in Celsius degre
Anton [14]

Answer:204.4

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
In 1898 L. J. Bortkiewicz published a book entitled The Law of Small Numbers. He used data collected over 20 years to show that
attashe74 [19]

Answer:

(a) The probability of more than one death in a corps in a year is 0.1252.

(b) The probability of no deaths in a corps over 7 years is 0.0130.

Step-by-step explanation:

Let <em>X</em> = number of soldiers killed by horse kicks in 1 year.

The random variable X\sim Poisson(\lambda = 0.62).

The probability function of a Poisson distribution is:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!};\ x=0,1,2,...

(a)

Compute the probability of more than one death in a corps in a year as follows:

P (X > 1) = 1 - P (X ≤ 1)

             = 1 - P (X = 0) - P (X = 1)

             =1-\frac{e^{-0.62}(0.62)^{0}}{0!}-\frac{e^{-0.62}(0.62)^{1}}{1!}\\=1-0.54335-0.33144\\=0.12521\\\approx0.1252

Thus, the probability of more than one death in a corps in a year is 0.1252.

(b)

The average deaths over 7 year period is: \lambda=7\times0.62=4.34

Compute the probability of no deaths in a corps over 7 years as follows:

P(X=0)=\frac{e^{-4.34}(4.34)^{0}}{0!}=0.01304\approx0.0130

Thus, the probability of no deaths in a corps over 7 years is 0.0130.

6 0
3 years ago
What's the estimate of 6.48 + 9.34?
Alex_Xolod [135]

Answer:

16

Step-by-step explanation:

6.48 + 9.34= 15.82 so when u round the number it 16 so the estimate is 16.

6 0
2 years ago
The one selected is wrong please help meee!
GREYUIT [131]

Answer:

  (a)  ΔARS ≅ ΔAQT

Step-by-step explanation:

The theorem being used to show congruence is ASA. In one of the triangles, the angles are 1 and R, and the side between them is AR. The triangle containing those angles and that side is ΔARS.

In the other triangle, the angles are 3 and Q, and the side between them is AQ. The triangles containing those angles and that side is ΔAQT.

The desired congruence statement in Step 3 is ...

  ΔARS ≅ ΔAQT

5 0
2 years ago
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