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Nataly [62]
3 years ago
8

Solving exponential equations 5^x-1 = 125

Mathematics
1 answer:
wariber [46]3 years ago
7 0

Answer:

x = 4

Step-by-step explanation:

5^(x-1) = 125

log₅(5^(x-1)) = log₅(125)

x-1 = 3

x = 4

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Choose the correct solution and graph inequality q + 1/3 &gt; 1/2​
kherson [118]

Answer:

first choice

Step-by-step explanation:

make 1/3 and 1/2 a common denominator, which is 6.

1x2

-      = 2

         -

3x 2   6

1 x 3  

-       =    3

             -

2 x 3      6

now u have 2/6, and 3/6

u subtract 2/6 by 3/6 since ur finding a solution to an inequality. remember to do the opposite sign.

2/6-2/6 = 0 (u cancel that out)

3/6 - 2/6 = 1/6

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q>1/6

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7 0
3 years ago
A sheet of paper 90 cm-by-66 cm is made into an open box (i.e. there's no top), by cutting x-cm squares out of each corner and f
NNADVOKAT [17]

Answer:

26 - \sqrt{181} cm

Step-by-step explanation:

The volume of the box is:

V = height * length * width

V = x*(66 - 2*x)*(90 - 2*x)

V = (66*x - 2*x^2)*(90 - 2*x)

V = 5940*x - 132*x^2 - 180*x^2 + 4*x^3

V = 4*x^3 - 312*x^2 + 5940*x

where x is the length of the sides of the squares,  in cm.

The mathematical problem is :

Maximize: V = 4*x^3 - 312*x^2 + 5940*x

subject to:

x > 0

2*x < 66 <=> x < 33

In the maximum, the first derivative of V, dV/dx, is equal to zero

dV/dx = 12*x^2 - 624*x + 5940

From quadratic formula

x = \frac{-b \pm \sqrt{b^2 - 4(a)(c)}}{2(a)}

x = \frac{624 \pm \sqrt{(-624)^2 - 4(12)(5940)}}{2(12)}

x = \frac{624 \pm \sqrt{104256}}{24}

x = \frac{624 \pm \sqrt{2^6*3^2*181}}{24}

x = \frac{624 \pm 8*3*\sqrt{181}}{24}

x_1 = \frac{624 + 24*\sqrt{181}}{24}

x_1 = 26 + \sqrt{181}

x_2 = \frac{624 - 24*\sqrt{181}}{24}

x_2 = 26 - \sqrt{181}

But x_1 > 33, then is not the correct answer.

5 0
3 years ago
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