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3 years ago

Determine whether or not it is a function

Mathematics

1 answer:

Brrunno [24]3 years ago

4 0

This is indeed a function because every domain is only used once, a domain can indeed share a range but can’t be the same for which it’s a function due to the fact that no domain is repeated with a different outcome

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A bag contains 6 red jelly beans, 4 green jelly beans, and 4 blue jelly beans.

worty [1.4K]

The simplified probability would be 12/91.

There are 4 green jelly beans out of a total of 14 jelly beans. The probability for the first bean would be 4/14.

Once the first jelly bean is removed, the probability that the second jelly bean would be red is 6/13 (the denominator decreases by 1 because of the first jelly bean that did not get put back).

Together the probability is (4/14)(6/13) = 24/182, which then simplifies to 12/91.

7 0

4 years ago

Read 2 more answers

What is the ratio of 1:3=3:

Nuetrik [128]

Answer:

Step-by-step explanation:

1*3 = 3 and 3*3 = 9

So the answer is 9

Hope this helps!

3 0

3 years ago

Use Stokes' Theorem to evaluate S curl F · dS. F(x, y, z) = x2 sin(z)i + y2j + xyk, S is the part of the paraboloid z = 9 − x2 −

Korolek [52]

The vector field

$\vec F(x,y,z)=x^2\sin z\,\vec\imath+y^2\,\vec\jmath+xy\,\vec k$

has curl

$\nabla\times\vec F(x,y,z)=x\,\vec\imath+(x^2\cos z-y)\,\vec\jmath$

Parameterize $S$ by

$\vec s(u,v)=x(u,v)\,\vec\imath+y(u,v)\,\vec\jmath+z(u,v)\,\vec k$

where

$\begin{cases}x(u,v)=u\cos v\\y(u,v)=u\sin v\\z(u,v)=(9-u^2)\end{cases}$

with $0\le u\le3$ and $0\le v\le2\pi$ .

Take the normal vector to $S$ to be

$\dfrac{\partial\vec s}{\partial u}\times\dfrac{\partial\vec s}{\partial v}=2u^2\cos v\,\vec\imath+2u^2\sin v\,\vec\jmath+u\,\vec k$

Then by Stokes' theorem we have

$\displaystyle\int_{\partial S}\vec F\cdot\mathrm d\vec r=\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S$

$=\displaystyle\int_0^{2\pi}\int_0^3(\nabla\times\vec F)(\vec s(u,v))\cdot\left(\dfrac{\partial\vec s}{\partial u}\times\dfrac{\partial\vec s}{\partial v}\right)\,\mathrm du\,\mathrm dv$

$=\displaystyle\int_0^{2\pi}\int_0^3u^3(2u\cos^3v\sin(u^2-9)+\cos^3v\sin v+2u\sin^3v+\cos v\sin^3v)\,\mathrm du\,\mathrm dv$

which has a value of 0, since each component integral is 0:

$\displaystyle\int_0^{2\pi}\cos^3v\,\mathrm dv=0$

$\displaystyle\int_0^{2\pi}\sin v\cos^3v\,\mathrm dv=0$

$\displaystyle\int_0^{2\pi}\sin^3v\,\mathrm dv=0$

$\displaystyle\int_0^{2\pi}\cos v\sin^3v\,\mathrm dv=0$

4 0

3 years ago

Select the three models that represent 45%

Volgvan

Answer:

hi pls mark me brain list

7 0

3 years ago

A class of sixty voted for class president 30% voted brad and 70% voted for Jane how many votes did the winner get

brilliants [131]

When working with percents change them to decimals so 70% is .70 because a percent is just the number over 100. If you try it yourself do 70 divided by 100 and see what you get. For this problem you then multiply that by sixty as the total number of people included, which gets you 42 votes.

8 0

4 years ago

Determine whether or not it is a function ​

Determine whether or not it is a function