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spayn [35]
2 years ago
5

Exponent laws and pythagorean theorem quiz

Mathematics
1 answer:
Vikentia [17]2 years ago
6 0

Answer:

12.2

Step-by-step explanation:

A^2 + B^2 = C^2

(7)^2 + (10)^2 = (C)^2

49 + 100 = C^2

149 = C^2

sqr(149) = C

12.2 = C

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I need help on this 2 problems please help​
daser333 [38]
<h3>Answer:</h3>

  7)  0.76 is a rational number

  8)  The list of favorable outcomes is {orange pop #1, orange pop #2}.

<h3>Step-by-step explanation:</h3>

7) The product 0.4 × 1.9 is 0.76. This is not an integer, whole number, or natural number. It is a decimal fraction of finite length, so is a rational number.

___

8) Often, a problem of this sort will ask for the probability of an orange pop outcome. This problem doesn't ask that. Rather it asks what the possible orange pop outcomes are. Drawing one orange pop from the box will give you one of ...

  • orange pop #1
  • orange pop #2

These are the possible outcomes.

5 0
3 years ago
Esmeralda rent a car from a company that race cars by an hour she has a pair nishal fee of $52 and then they charged her $8 per
tatuchka [14]

Answer:

11 hours is the most she can afford

Step-by-step explanation:


7 0
3 years ago
A cola-dispensing machine is set to dispense 8 ounces of cola per cup, with a standard deviation of 1.0 ounce. The manufacturer
pshichka [43]

Answer:

Step-by-step explanation:

Hello!

The variable of interest is X: ounces per cup dispensed by the cola-dispensing machine.

The population mean is known to be μ= 8 ounces and its standard deviation σ= 1.0 ounce. Assuming the variable has a normal distribution.

A sample of 34 cups was taken:

a. You need to calculate the Z-values corresponding to the top 5% of the distribution and the lower 5% of it. This means you have to look for both Z-values that separates two tails of 5% each from the body of the distribution:

The lower value will be:

Z_{o.o5}= -1.648

You reverse the standardization using the formula Z= \frac{X[bar]-Mu}{\frac{Sigma}{\sqrt{n} } } ~N(0;1)

-1.648= \frac{X[bar]-8}{\frac{1}{\sqrt{34} } }

X[bar]= 7.72ounces

The lower control point will be 7.72 ounces.

The upper value will be:

Z_{0.95}= 1.648

1.648= \frac{X[bar]-8}{\frac{1}{\sqrt{34} } }

X[bar]= 8.28ounces

The upper control point will be 8.82 ounces.

b. Now μ= 7.6, considering the control limits of a.

P(7.72≤X[bar]≤8.28)= P(X[bar]≤8.28)- P(X[bar]≤7.72)

P(Z≤(8.28-7.6)/(1/√34))- P(Z≤7.72-7.6)/(1/√34))

P(Z≤7.11)- P(Z≤0.70)= 1 - 0.758= 0.242

There is a 0.242 probability of the sample means being between the control limits, this means that they will be outside the limits with a probability of 1 - 0.242= 0.758, meaning that the probability of the change of population mean being detected is 0.758.

b. For this item μ= 8.7, the control limits do not change:

P(7.72≤X[bar]≤8.28)= P(X[bar]≤8.28)- P(X[bar]≤7.72)

P(Z≤(8.28-8.7)/(1/√34))- P(Z≤7.72-8.7)/(1/√34))

P(Z≤-2.45)- P(Z≤-5.71)=0.007 - 0= 0.007

There is a 0.007 probability of not detecting the mean change, which means that you can detect it with a probability of 0.993.

I hope it helps!

5 0
2 years ago
Read 2 more answers
PLS HELP will give brainliest answer both
wariber [46]

Answer:

8 3/5

false

Step-by-step explanation:

4 0
3 years ago
Divide. −4 1/3 ÷ −2 3/5 A. 1 2/3 B. 1 4/5 C. 2 1/5 D. 2 3/5
Inga [223]

a. 1 \frac{2}{3}

trust me it's the correct answer :)

7 0
3 years ago
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