Answer:
Offer as much extraneous information as possible. The viewer will decide what is important.
The answer to your question is b crowding out effect
Answer:
In C:
#include <stdio.h>
#include <math.h>
int main(){
float f0,r,temp;
r = pow(2.0,1.0/12);
printf("f0: "); scanf("%f", &f0);
temp = f0;
for(int i = 0; i<=4;i++){
f0 = f0 * pow(r,i);
printf("%.2lf ", f0);
f0 = temp; }
return 0;
}
Explanation:
This declares f0, r and temp as float
float f0,r,temp;
This initializes r to 2^(1/12)
r = pow(2.0,1.0/12);
This prompts the user for f0
printf("f0: "); scanf("%f", &f0);
This saves f0 in temp
temp = f0;
This iterates the number of keys from 0 to 4
for(int i = 0; i<=4;i++){
This calculates each key
f0 = f0 * pow(r,i);
This prints the key
printf("%.2lf ", f0);
This gets the initial value of f0
f0 = temp; }
return 0;
Answer:
// Producer Thread
void *producer(void *param) {
buffer_item item;
while (true) {
item = rand() % 100;
sem_wait(&empty);
pthread_mutex_lock(&mutex);
if (insert_item(item))
printf("Can't insert item\n");
else
printf("Producer %d: produced %d\n", *((int*)param), item);
pthread_mutex_unlock(&mutex);
sem_post(&full);
}
}
// Consumer Thread
void *consumer(void *param) {
while (true) {
buffer_item item = NULL;
if (in > 0)
item = buffer[in - 1];
sem_wait(&full);
pthread_mutex_lock(&mutex);
if (remove_item(&item))
printf("Can't remove item\n");
else
printf("Consumer %d: consumed %d\n", *((int*)param), item);
pthread_mutex_unlock(&mutex);
sem_post(&empty);
}
}
Explanation:
An outline of the producer and consumer threads appears as shown above.
Answer:
Receiving unexpected results from a program
Explanation:
Logic errors are due to the program not producing a desired result.
